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3 years ago

Work out the circumference of this circle.

Mathematics

2 answers:

kirill [66]3 years ago

4 0

Answer:

62.84

Step-by-step explanation:

pie=3.142

c=pie * diameter

r=10cm

d=2r

d=2(10)=20cm

c=3.142 * 20

c=62.84

Levart [38]3 years ago

3 0

Step-by-step explanation:

Formula for the Circumference of a circle = 2πr

C = 2πr

C = (2 * 3.142) * 10

C = 6.284 * 10

C = 62.84cm

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3O POINTS!! AND I WILL MARK THE BRAINLEST ANSWER EVER PLZ HELPP MEEE

AysviL [449]

Answer: Use order of operations (PEMDAS). Answer is 45.72.

Step-by-step explanation:

First, solve inside parenthesis:

(5.25*1 1/5 - 4.5*4/5)

Convert 1 1/5 into decimal. It will be easier. 1 1/5 is the same as 1.2

Do multiplication and division first.

5.25*1.2 = 6.3

Now it looks like: (6.3 - 4.5*4/5)

Convert 4/5 to a decimal: 4/5 = 0.8

(6.3 - 4.5*0.8)

Multiply 4.5*0.8 = 3.7

Subtract (6.3 - 3.7) = 2.6

Now the full equation is: 19.6*2 1/5 + (2.6)

2 1/5 as a decimal: 2.2

Multiply 19.6*2.2 = 43.12

Now the equation is: 43.12 + 2.6

Add 43.12 + 2.6 = 45.72

4 0

3 years ago

Mario invested $6,000 in an account that pays 5% annual interest compounded annually how much will be there after 2.5 years

Liono4ka [1.6K]

Answer:

$48,000

Step-by-step explanation:

$i = \frac{p \times r \times t}{100 } \\ 6000 = \frac{p \times 5 \times 2.5}{100 } \\ 600000 = 12.5 \\ 48000$

6 0

2 years ago

Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt

tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

$f(x)= \sqrt{\dfrac{x+1}{x-1}}$

$g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}$

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

$\dfrac{x+1}{x-1}>0$

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

$x+1\leq 0\Rightarrow x\leq -1$

$x-1\leq 0\Rightarrow x\leq 1$

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0

3 years ago

ASAP 55 points Which expression is equivalent to ((x^(-4)y)/(x^(-9)y^(5)))^(-2) assume x = 0 ,y = 0

german

Answer:

I thought if you try to do an exponent on a zero, then the answer would always be undefined...

Step-by-step explanation:

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3 years ago

(3,y) (1,4) m= -2 what is the value of y if the line through the two given points is to have indicated slope

riadik2000 [5.3K]

Answer:

y=0

Step-by-step explanation:

The equation for the slope is

m = ( y2-y1)/(x2-x1)

-2 = (4-y)/(1-3)

-2 = (4-y)/-2

Multiply each side by -2

4 = 4-y

Subtract 4 from each side

4-4 = 4-y-4

0 = -y

0=y

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3 years ago