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professor190 [17]
2 years ago
9

HIJK is a parallelogram because the midpoint of both diagonals is ____, which means the diagonals bisect each other. What goes i

n the blank?
A. (1, -1)
B. (1, 1)
C. (1, 0)
D. (0, 1)

Mathematics
2 answers:
Nostrana [21]2 years ago
8 0

Answer:

1,0 just took it on ED

Step-by-step explanation:

Nikolay [14]2 years ago
3 0
<span>C. (1,0) This is a simple matter of determining the midpoint of both diagonals. The 1st diagonal is from point H(-2,2) to point J(4,-2). And the midpoint is simply the average of both points. So you get: ((-2+4)/2, (2-2)/2) = (2/2, 0/2) = (1, 0) And the 2nd diagonal is from point I(4,3) to point K(-2,-3). And its midpoint is ((4-2)/2, (3-3)/2) = (2/2, 0/2) = (1, 0) So you see that the midpoint of both diagonals is the same (1,0) and that matches option C.</span>
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11Alexandr11 [23.1K]

Answer:

4y-x

Step-by-step explanation:

Combine like-terms.

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3 years ago
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zepelin [54]

Answer:

(c-a, 0)

Step-by-step explanation:

The horizontal space between (c, b) and P is the same as the space between (a, b) and O.

Coordinates are written (x, y), where x is for horizontal space.

P is on the x-axis, making the y-coordinate 0.

(a+c, 0) would be to the right of the entire parallelogram.

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4 0
3 years ago
Tienes un triángulo equilátero con lados de 10cm, lo divides en dos partes de manera horizontal tal que el área de ambos figuras
Tanya [424]

Answer:

x = 10/√2 ≈ 7.07

Step-by-step explanation:

Comenzaremos por dividir el triángulo en dos partes y definir H, como en la figura adjunta.

Aplicando el teorema de Tales, sabemos que:

\dfrac{l/2}{H}=\dfrac{x/2}{h}\\\\\\\dfrac{l}{H}=\dfrac{x}{h}

También sabemos que, dado que el tirángulo menor es la mitad que el triángulo mayor, la relación entre áreas es:

\dfrac{A}{A_x}=\dfrac{lH/2}{xh/2}=\dfrac{lH}{xh}=2

Dado que formamos dos triángulos rectángulos, podemos despejar el valor de H como:

(l/2)^2+H^2=l^2\\\\H^2=l^2-(l/2)^2=10^2-5^2=100-25=75\\\\H^2=\sqrt{75}

Podemos entonces despejar x de la siguiente manera:

h=\dfrac{H}{l}\cdot x=\dfrac{lH}{2x}\\\\\\2x^2\dfrac{H}{l}=lH\\\\\\2x^2=l^2\\\\\\x=\dfrac{l}{\sqrt{2}}=\dfrac{10}{\sqrt{2}}\approx7.07

6 0
3 years ago
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Firlakuza [10]

Answer:

Step-by-step explanation:

7 0
2 years ago
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