Can somebody please help me with this equation

What is the value of x in the regular polygon? The value of x is?

brilliants [131]

Answer:

.

Step-by-step explanation:

8 0

3 years ago

How to solve this algebraically?

Keith_Richards [23]

Ok so x+4-1 makes x-1 so i belive the answer could be 1/5

7 0

3 years ago

Read 2 more answers

The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price

likoan [24]

Answer:

A) 3%

B) Product A

Step-by-step explanation:

Exponential Function

General form of an exponential function: $y=ab^x$

where:

a is the initial value (y-intercept)
b is the base (growth/decay factor) in decimal form
x is the independent variable
y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

Part A

Product A

Assuming the function for Product A is exponential:

$f(x) = 0.69(1.03)^x$

The base (b) is 1.03. As b > 1 then it is an increasing function.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, product A is increasing by 3% each year.

Part B

$\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100$

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

$\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%$

Check using different two consecutive values of f(t):

$\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%$

Therefore, as 3% > 1%, Product A recorded a greater percentage change in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

a = 10,100
b = 1.01
n = t - 1 (as the initial value is for t = 1 not t = 0)

$\implies f(t) = 10100(1.01)^{t-1}$

To check this, substitute the values of t for 1 through 4 into the found function:

$\implies f(1) = 10100(1.01)^{1-1}=10100$

$\implies f(2) = 10100(1.01)^{2-1}=10201$

$\implies f(3) = 10100(1.01)^{3-1}=10303.01$

$\implies f(4) = 10100(1.01)^{4-1}=10406.04$

As these values match the values in the given table, this confirms that the found function for Product B is correct and that Product B increases by 1% per year.

4 0

2 years ago

Which of the following best describes perpendicular lines

Usimov [2.4K]

Answer:

B.

Step-by-step explanation:

Perpendicular lines always intercept at a right angle (90 degrees).

8 0

3 years ago

Read 2 more answers

Carmen and Matt are conducting different chemistry experiments in school. In both experiments, each student starts with an initi

dangina [55]

This question is incomplete and it lacks an attached graph. Find attached to this answer, the appropriate graph.

Complete Question

Carmen and Matt are conducting different chemistry experiments in school. In both experiments, each student starts with an initial amount of water in a flask. They combine two chemicals which react to produce more water. Carmen's experiment starts with 30 milliliters of water in a flask, and the water increases in volume by 8.5 milliliters per second. Matt's experiment starts with 10 milliliters of water and increases in volume by 28% each second. The graph represents the volume of water in the two flasks in relation to time. Which two conclusions can be made if f represents the volume of water in Carmen's flask and g represents the volume of water in Matt's flask? a) The volume of water in Carmen's flask is increasing at a slower rate than the volume of water in Matt's flask over the interval [0, 2].

b) The volume of water in Carmen's flask is increasing at a faster rate than the volume of water in Matt's flask over the interval [6, 8].

c) The volume of water in Carmen's flask will always be greater than the volume of water in Matt's flask.

d) The volume of water in Matt's flask will eventually be greater than the volume of water in Carmen's flask.

e) The volume of water in Carmen's flask is increasing at a slower rate than the volume of water in Matt's flask over the interval [4, 6].

Answer:

c) The volume of water in Carmen's flask will always be greater than the volume of water in Matt's flask.

e) The volume of water in Carmen's flask is increasing at a slower rate than the volume of water in Matt's flask over the interval [4, 6].

Step-by-step explanation:

Looking at the graph, the average rate of change is given as [0,2], [4,6], and [6,8].

From the graph and question, we can tell that Matt's experiment starts with 10 milliliters of water and increases in volume by 28% each second

Which would gives us:

28% of 10 milliliter of water = 2.8 millimeters per second.

For Carmen , his experiment starts with 30 milliliters of water in a flask, and the water increases in volume by 8.5 milliliters per second,

Because, Carmen starts with 30 milliliters of water in his flask, the volume of water in Carmen's flask will always be greater than the volume of water in Matt's flask.

Secondly, comparing the quantity as which the volume of the flask increases per second, at the interval of [4, 6], the volume of water in Carmen's flask is increasing at a slower rate than the volume of water in Matt's flask over the interval

7 0

3 years ago