All categories

2 years ago

What’s 9 times 9 Just gave you 100 for free your welcome

Mathematics

2 answers:

Rudiy272 years ago

6 0

Answer:

81! THANK YOU<3333333333333

Mrac [35]2 years ago

6 0

Answer: 81

Step-by-step explanation: 9 x 9 = 81 Obviously

You might be interested in

1. The graph of y = x2 is translated 4 units down and 3 units to the left. It is also stretched by a factor

slega [8]

Answer:

ok so first ur gonna do 4x3=12 then

Step-by-step explanation:

7 0

2 years ago

A traveling soccer team allows only the top 3% of athletes who try out to be part of the team. If the team tryout scorecard has

skad [1K]

Answer:

169

Step-by-step explanation:

You need to use a Z-table for this.

There are different tables, in this table i searched for the probability of 97% because that equivalent to the top 3%.

for 0.97, Z = 1.88

The formula of Z is:

$Z = (x-mean)/(st. dev.)$

Solving x:

$1.88 = (x-150)/10 \\x = 168.8 = 169$

3 0

3 years ago

Read 2 more answers

Which equation can be solved using the expression StartFraction negative 3 plus-or-minus StartRoot (3) squared + 4 (10) (2) EndR

katen-ka-za [31]

Answer: B. 2 = 3x + 10x2

Step-by-step explanation:

This is the concept of quadratic equations; We required to find the type of equation that can be solved using the model that has been used to solve the equation such that the answer is:

[-3+-sqrt(3^2+4(10)(2))]/(2(10))

The formual that was applied here was a quadratic formula given by:

x=[-b+\-sqrt(b^2-4ac)]/2a

whereby from the our substituted values above,

a=10,b=3 and c=-2

such that the quadratic equation will be:

10x^2+3x-2

3 0

3 years ago

Read 2 more answers

Giving 10 points need urgently

larisa86 [58]

Answer:

{-2, - 1, 0, 1}

Step-by-step explanation:

The integer solutions will be {-2, - 1, 0, 1}

3 0

2 years ago

Read 2 more answers

An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de

Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

$P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721$

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

$P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have:

$P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528$

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

$P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have

$P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453$

The sum of the probabilities is

$P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981$

8 0

3 years ago