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2 years ago

Recall that the volume of a sphere is given by the formula V = 4/3pi to the 3rd

Mathematics

1 answer:

Kisachek [45]2 years ago

4 0

9514 1404 393

Answer:

1. (256/3)π ft³

2. 33.49 ft³

Step-by-step explanation:

1. Put 4 ft into the formula where r is, then simplify.

V = (4/3)π(4 ft)³ = (256/3)π ft³

2. The radius is half the diameter, so is 2 ft. Put that in the formula, along with the value for π, and do the arithmetic.

V = (4/3)(3.14)(2 ft)³ ≈ 33.49 ft³

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3 years ago

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2 years ago

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2 years ago

Using Unit Rates to compare Ratios continued

nasty-shy [4]

Answer:

Brandon

Step-by-step explanation:

GIVEN: Branden and Pete each play running back. Branden carries the ball $75$ times for $550$ yards, and Pete has $42$ carries for $380$ yards.

TO FIND: Who runs farther per carry.

SOLUTION:

Total yards traveled by Brandon $=550\text{yards}$

No. of times ball carried by Brandon $=75\text{ times}$

Average yards per carry for Brandon $=\frac{\text{total yards traveled}}{\text{number of times ball carried}}$

$=\frac{550}{75}$

$=\frac{22}{3}\text{ yards per carry}$

$=7.33\text{ yards per carry}$

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No. of times ball carried by Pete $=42\text{ times}$

Average yards per carry for Pete $=\frac{\text{total yards traveled}}{\text{number of times ball carried}}$

$=\frac{380}{42}$

≅ $9\text{ yards per carry}$

As the number of yards per carry is higher for Brandon , therefore he runs farther per carry.

4 0

3 years ago

The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d

EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable X represent the miles-per-gallon rating of passenger cars.

It is provided that $X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2})$ .

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

$P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})$

$=P(Z>1)\\\\=1-P(Z$

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

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2 years ago