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jeka57 [31]
3 years ago
12

Answer cant get hang of it answers anyone please

Mathematics
1 answer:
saveliy_v [14]3 years ago
7 0
4). 9x=49

6). n+5=6

8). m^3

10). 7+5
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What will be the unit digit of the cube of a number ending with 9 ?
Bess [88]

Answer:

9

Step-by-step explanation:

If I’m understanding you correctly, the answer would be nine.  Any number with a 9 in the one’s place (unit digit) would still have a nine in that place after being cubed.

29³=24,389

69³=328,509

3 0
3 years ago
Read 2 more answers
Can you think of another combination of triangle classification that is impossible?
cestrela7 [59]
How about an equilateral right triangle or equiangular right triangle hope this helps
3 0
3 years ago
Write the equation of the line in fully simplified slope-intercept form.
Ostrovityanka [42]
Y = 3x - 1
-------------
5 0
3 years ago
The probability
Verdich [7]

Probability of distinct 3-digits is 1/6.

Probability of both the first digit and the last digit are even numbers is 1/5.

<u>Step-by-step explanation</u>:

Given set of numbers {1,2,3,5,8,9} = 6

Total number of 3-digits can be formed = 6\times5\times4 = 120.

<u>Probability  of the three-digit numbers with distinct digits</u> :

The number of 3-digit numbers with distinct digits = (6\times5\times4) / (3\times2\times1) = 20.

P(distinct 3-digits) =  no. of distinct 3-digits / Total no.of 3-digits

⇒ 20/120

⇒ 1/6

<u>Probability that both the first digit and the last digit of the three-digit number are even numbers</u> :

The even numbers in the set are 2 and 8 = 2 possibilities.

The number of 3-digits with 1st and 3rd digit are even = (2\times6\times2) = 24.

P(1st and 3rd digits even)= no. of 1st and 3rd digit even/Total no. of 3-digits.

⇒ 24/120

⇒ 1/5

6 0
4 years ago
Recently, FHA mortgages, which are insured by the federal government, accounted for 28% of all home-purchase mortgages that were
Murljashka [212]

Answer:

15.87% probability that 48 or more from this sample were insured by the FHA

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.28, n = 150

So

\mu = E(X) = np = 150*0.28 = 42

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{150*0.28*0.72} = 5.5

What is the probability that 48 or more from this sample were insured by the FHA?

Using continuity correction, this is P(X \geq 48 - 0.5) = P(X \geq 47.5), which is 1 subtracted by the pvalue of Z when X = 47.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{47.5 - 42}{5.5}

Z = 1

Z = 1 has a pvalue of 0.8413.

1 - 0.8413 = 0.1587

15.87% probability that 48 or more from this sample were insured by the FHA

4 0
4 years ago
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