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Setler [38]
3 years ago
7

Which of the following could be the name of a point

Mathematics
2 answers:
liberstina [14]3 years ago
6 0
They are called ordered pairs. (x,y)
Elis [28]3 years ago
6 0

Answer:

<h2>A. a</h2>

Step-by-step explanation:

The options for this question are:

A. a

B. m

C. \vec A

D. AB.

So, among the options the first one can be the name of a point. Basically, because <em>m </em>means slope, \vec A is used to name vector, because it has the arrow on top. And AB is used to name segments, where A is the beginning and B if the ending.

Therefore, the right answer is A.

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How do you solve the proportion7/5=x/3 ??
mote1985 [20]
The way I like to solve proportions is by cross multiplying and dividing. First yo multiply the diagonals and then you divide by the other number. So if your proportion is 7/5 = x/3, your equation would be 7*3/5.  So 7*3 is 21, so your equation is now 21/5.  With some long division, you'll see that 21/5 = 4.2  That's your answer, feel free to ask more questions if you need!!(:
5 0
3 years ago
Read 2 more answers
Solve for c.<br><br> 3 − 7c − 20c = 7(–7c − 19) + 14c<br><br> c =
OleMash [197]

Answer:

\boxed{c = -17}

Step-by-step explanation:

=  > 3 - 7c - 20c = 7( - 7c - 19) + 14c \\  \\  =  > 3 - 27c = ( - 7c \times 7) - (7 \times 19) + 14c \\  \\  =  > 3 - 27c =  - 49c - 133 + 14c \\  \\  =  > 3 - 27c =  - 35c - 133 \\  \\  =  > 3 - 27c + 35c =  - 133 \\  \\  =  > 3  + 8c =  - 133 \\  \\  =  > 8c =  - 133 - 3 \\  \\  =  > 8c =  - 136 \\  \\  =  > c =  -  \frac{136}{8}  \\  \\  =  > c =  - 17

7 0
3 years ago
Read 2 more answers
5•11+5•(-4)=5(11-4) wich property?​
ludmilkaskok [199]

Answer:

Step-by-step explanation:

55

3 0
3 years ago
Please help me on this ​
Zanzabum

Answer:

c

Step-by-step explanation:

7 0
3 years ago
Carlos is using the quadratic formula to find the solutions of y=3x^2-5x-2. Which of the following will simplify to the correct
Nana76 [90]

Answer:

Fx=\frac{5\pm\sqrt{25+24} }{6}

Step-by-step explanation:

A quadratic equation in one variable given by the general expression:

ax^2+bx+c

Where:

a\neq 0

The roots of this equation can be found using the quadratic formula, which is given by:

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

So:

y(x)=3x^2-5x-2=0

As you can see, in this case:

a=3\\b=-5\\c=-2

Using the quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}=\frac{-(-5)\pm\sqrt{(-5)^2-4(3)(-2)} }{2(3)}=\frac{5\pm\sqrt{25+24} }{6}

Therefore, the answer is:

Fx=\frac{5\pm\sqrt{25+24} }{6}

4 0
3 years ago
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