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3 years ago

A triangle cannot have more than one obtuse angle true or false

2 answers:

7 0

The answer is true;
because if a triangle had more than one obtuse angle it would become like a rhombus or something else so it is not possible to remain a triangle and have more than one obtuse angle c:

kipiarov [429]3 years ago

3 0

Answer:

True

Step-by-step explanation:

According to the Angle Sum property of triangle, Sum of all interior of a triangle is equal to 180°.

If there is more than one obtuse angle in a triangle then Sum of both obtuse angle exceed the maximum sum of all three angle of a triangle. Which contradict the Angle Sum Property of triangle.

So, It is impossible to have a triangle with two obtuse angles.

Only possible is a triangle with 1 obtuse angle with 2 acute angles.

Therefore, Answer for given statement is TRUE

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7. All quadrilaterals have 4 sides and a trapezoid is a quadrilateral. How many sides does a trapezoid have? A: 5 B: 4 C: 3 D: 2

nata0808 [166]

Answer:

B: 4

Step-by-step explanation:

A trapezoid have 4 sides.

Hope it helps you in your learning process

5 0

2 years ago

Read 2 more answers

Is this a function ? Yes or no and why or why not

never [62]

Answer:

Yes

Step-by-step explanation:

Yes it is a function, because graph is intersecting y - axis only once.

3 0

3 years ago

Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0

1 year ago

Express x^2y^2+x^2+y^2+1

Hitman42 [59]

Answer:

( y^2 +1) ( x^2+1)

Step-by-step explanation:

Step 1 ) Factor out x^2 from the expression

x^2 (y^2+1)+y^2+1

Step 2) Factor out y^2 from the expression

(y^2+1) (x^2+1)

Solution is ( y^2 +1) ( x^2+1)

5 0

2 years ago

1-2 Cos²25°÷(1-2sin²25)<br>

shusha [124]

Answer:

have a good one

Step-by-step explanation:

6 0

2 years ago