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Sloan [31]
3 years ago
8

A triangle cannot have more than one obtuse angle true or false

Mathematics
2 answers:
anastassius [24]3 years ago
7 0
The answer is true;
 because if a triangle had more than one obtuse angle it would become like a rhombus or something else so it is not possible to remain a triangle and have more than one obtuse angle c:
kipiarov [429]3 years ago
3 0

Answer:

True

Step-by-step explanation:

According to the Angle Sum property of triangle, Sum of all interior of a triangle is equal to 180°.

If there is more than one obtuse angle in a triangle then Sum of both obtuse angle exceed the maximum sum of all three angle of a triangle. Which contradict the Angle Sum Property of triangle.

So, It is impossible to have a triangle with two obtuse angles.

Only possible is a triangle with 1 obtuse angle with 2 acute angles.

Therefore, Answer for given statement is TRUE

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In order to make 6 dozen cookies, you must use 3 eggs in the batter. How many eggs would be required to make 48 dozen cookies? U
Brrunno [24]

24

Step-by-step explanation:

Well 6 times 8 is 48 so

8 times 3 is 24

7 0
3 years ago
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What is blank divided by 9 equals 5
Rudik [331]

Answer:

45 divided by 9 equals 5

Step-by-step explanation:

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Find the area of the regular polygon in square units. Please help . It’s number 5
Juliette [100K]

Answer:

The triangle goes into the square 8 times.  Find the area of the triangle and multiply by 8 :) hope this helps, let me know if you need more of an explanation.

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Please help, solve for x
statuscvo [17]

Answer:

x = 6

Step-by-step explanation:

10x = 5 x 12 = 60

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6 0
3 years ago
Can someone please help I really need these points
spayn [35]

Given:

Two chords intersect each other inside the circle.

To find:

The value of x.

Solution:

According to intersecting chords theorem, if two chords intersect each other inside the circle, then the product of two segments of one chord is equal to  the product of two segments of second chord.

In the given circle,

AE\times CE=BE\times DE

(3x-11)\times (5x-4)=(x+2)\times (-x+17)

15x^2-12x-55x+44=-x^2+17x-2x+34

15x^2-67x+44+x^2-15x-34=0

16x^2-82x+10=0

Divide both sides by 2.

8x^2-41x+5=0

Splitting the middle term, we get

8x^2-40x-x+5=0

8x(x-5)-1(x-5)=0

(8x-1)(x-5)=0

Using zero product property, we get

(8x-1)=0 or (x-5)=0

x=\dfrac{1}{8} or x=5

For x=\dfrac{1}{8}, the side AE is negative. So, x=\dfrac{1}{8} is not possible.

Therefore, the required solution is x=5.

6 0
3 years ago
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