Answer:
4
Step-by-step explanation:
log2(16)
log2(2^4)
4 log2(2)
4 × 1
4
It should be 4
He can fill 6 boxes. 48 / 7 = 6R6.
I interpreted the remainder by removing the remainder to get the answer.
Answer:
It is a many-to-one relation
Step-by-step explanation:
Given
See attachment for relation
Required
What type of function is it?
The relation can be represented as:
![\left[\begin{array}{c}y\\ \\10\\11\\4\\10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dy%5C%5C%20%5C%5C10%5C%5C11%5C%5C4%5C%5C10%5Cend%7Barray%7D%5Cright%5D)
Where
and 
Notice that the range has an occurrence of 10 (twice)
i.e.
and 
In function and relations, when two different values in the domain point to the same value in the range implies that, <em>the relation is many to one.</em>
Answer:
180, 180, 148, 180, 148
Step-by-step explanation:
The two rules in play here are ...
- the sum of interior angles of a triangle is 180°
- the angles of a linear pair are supplementary (they total 180°)
__
The first of these rules answers the first two questions:
- interior angles total 180°
- angles 1, 3, 4 total 180°
We can subtract the measure of angle 1 from both sides of the previous equation to find the sum of the remaining two angles.
- angles 3 and 4 total 148°
The second rule answers the next question:
- angles 1 and 2 total 180°
As before, subtracting the value of angle 1 from both sides of the equation gives ...
_____
<em>Additional comment</em>
Of course, the subtraction property of equality comes into play, also. For some unknown, X, you have (in both cases) ...
X + 32° = 180°
X +32° -32° = 180° -32° . . . . . . subtraction property of equality
X = 148° . . . . . . . . simplify
In the first case, X is the sum of angles 3 and 4. In the second case, X is angle 2 only.
Hey there! :)
This figure is an irregular polygon. Regular polygons have side lengths that measure the same length. In this polygon, not all the sides are equal. Therefore, it is an irregular polygon.
Your answer is the 2nd choice ⇒ irregular polygon
Hope this helps :)