Solve the following system of equations 3x+4y=16 and -4x-3y = -19
1 answer:
3x + 4y = 16
-4x - 3y = -19
4( 3x + 4y = 16)
3( -4x - 3y = -19)
Distribute
12x + 16y = 64
-12x - 9y = -57
Now subtract both equations
7y = 7
/7 on both sides
y = 1
Substitute y = 1 in one of the equations.
3x + 4y = 16
3x + 4(1) = 16
-4 on both sides
3x = 12
/3 on both sides
x = 4
Answer:
x = 4
y = 1
You might be interested in
F(x)= 6x-4
f(x)=6*8-4
f(x)=48-4
f(x)=44
You will have to set up a system of equations
Answer:
trapezium that is the answet
