2 years ago

Solve the following system of equations 3x+4y=16 and -4x-3y = -19

1 answer:

4 0

3x + 4y = 16
-4x - 3y = -19

4( 3x + 4y = 16)
3( -4x - 3y = -19)
Distribute
12x + 16y = 64
-12x - 9y = -57
Now subtract both equations
7y = 7
/7 on both sides
y = 1

Substitute y = 1 in one of the equations.
3x + 4y = 16
3x + 4(1) = 16
-4 on both sides
3x = 12
/3 on both sides
x = 4

Answer:
x = 4
y = 1

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