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MatroZZZ [7]
3 years ago
6

what are three cases where a limit does not exist? (& can you give ex of functions of graphs that represent these cases) ...

?
Mathematics
1 answer:
maks197457 [2]3 years ago
8 0
<span>1.) Jump discontinuities - Any line that jumps at a point
2.) Infinite discontinuities (y = 1/(x))
3.) Oscillating discontinuities (sin(x) as polpak suggested)</span>
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A hot air balloon descends to the ground. The function h(t) = 210 – 15t can be used to describe the altitude of the balloon as i
Olin [163]
It is D if its correct i will explain why
4 0
3 years ago
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Evaluate 7j+5-8k when j=0.5 and k=0.25
dlinn [17]

So first you would substitute j and k in the expression.

7(0.5)+5-8(0.25)

3.5+5-2

It would equal 6.5

Hope this helps!

6 0
3 years ago
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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
I dont understand this equation.
amm1812
Where is the question and what is it?
4 0
2 years ago
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La caja rectangular que se ilustra en la figura tiene dimensiones de 8° x 6° x 4°. Calcule el ángulo ∅ formado por una diagonal
Klio2033 [76]

Answer:

really, hola adios si si si

Step-by-step explanation:

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