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MatroZZZ [7]
3 years ago
6

what are three cases where a limit does not exist? (& can you give ex of functions of graphs that represent these cases) ...

?
Mathematics
1 answer:
maks197457 [2]3 years ago
8 0
<span>1.) Jump discontinuities - Any line that jumps at a point
2.) Infinite discontinuities (y = 1/(x))
3.) Oscillating discontinuities (sin(x) as polpak suggested)</span>
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What are the x-intercepts of y=2x^2+6x-20?
NISA [10]

Answer:

the x-intercepts are -5 and 2

Step-by-step explanation:

y=2x^2+6x-20

x-intercept is when y is set equal to zero

So, y = 0

0 = 2x^2+6x-20

2x^3+6x-20 = 0\\Taking \ 2 \ common\\2(x^2+3x-10) = 0\\Dividing \ both \ sides \ by \ 2\\x^2+3x-10 = 0\\Using \ mid\ term \ break \ formula\\x^2+5x-2x-10 = 0\\x(x+5)-2(x+5)=0\\Taking \ (x+5) \ common\\(x+5)(x-2) = 0

Either,

x+5 = 0    <u><em> OR </em></u>    x-2 = 0

x = -5       <u><em> OR  </em></u>     x = 2

So, the x-intercepts are -5 and 2

7 0
3 years ago
Read 2 more answers
Perform the indicated operation. -10 + 15 <br><br> -5 <br> 5 <br> 25 <br> -25
Ulleksa [173]
The answer is 5 because if you add 10 to -10 it is 0 then add the 5 more and it is 5.
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