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klemol [59]
3 years ago
5

The fee to rent a hall for a wedding is $1450 plus $50 per hour. For how many hours can it be rented forband stay within a budge

t of $2100?
Mathematics
1 answer:
inysia [295]3 years ago
7 0
2,100-1,450= 650
650➗50= 13
you can rent 13 hours.
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What is 5(34)68+76 can u guys give me the answer I really need help
Ratling [72]
5x34= 170
68+76= 144
170+144= 314
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3 years ago
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PLEASE HELP I NEED THIS TURNED IN,
DerKrebs [107]

Answer:

3/3 is equivilant to 1.

Multiplying 6/4 by 1, would be 6/4. Also, multiplying 6/4 by 3/3 would be 18/12, which could be simplified to 6/4.

Hope this helps!    

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3 years ago
For the month of November in a certain​ city, 88​% of the days are cloudy. Also in the month of November in the same​ city, 54​%
Gnoma [55]

Answer:

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

Step-by-step explanation:

We have these following probabilities:

An 88% probability that the day is cloudy.

An 54% probability that the day is both foggy and cloudy.

What is the probability that a randomly selected day in November will be foggy if it is cloudy​?

This is the percentage of days that are cloudy and foggy divided by those that are cloudy. So:

P = \frac{0.54}{0.88} = 0.6136

There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.

4 0
3 years ago
An experiment to investigate the survival time in hours of an electronic component consists of placing the parts in a test cell
mixer [17]

Answer:

a) The sample mean is of 49 and the sample standard deviation is of 11.7.

b) The range of the true mean at 90% confidence level is of 9.62 hours.

c) The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

Step-by-step explanation:

Question a:

Sample mean:

\overline{x} = \frac{34+40+46+49+61+64}{6} = 49

Sample standard deviation:

s = sqrt{\frac{(34-49)^2+(40-49)^2+(46-49)^2+(49-49)^2+(61-49)^2+(64-49)^2}{5}} = 11.7

The sample mean is of 49 and the sample standard deviation is of 11.7.

b)Determine the range of the true mean at 90% confidence level.

We have to find the margin of error of the confidence interval. Since we have the standard deviation for the sample, the t-distribution is used.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.0.150

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. So

M = 2.0150\frac{11.7}{\sqrt{6}} = 9.62

The range of the true mean at 90% confidence level is of 9.62 hours.

(c)If a seventh sample is tested, what is the prediction interval (90% confidence level) of its failure time.

This is the confidence interval, so:

The lower end of the interval is the sample mean subtracted by M. So it is 49 - 9.62 = 39.38 hours.

The upper end of the interval is the sample mean added to M. So it is 49 + 9.62 = 58.62 hours.

The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

4 0
3 years ago
Two parallel lines are crossed by a traversal. What is the value of b?
nika2105 [10]

Answer:

b = 128 answers it is alternate angle

7 0
2 years ago
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