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Marat540 [252]
4 years ago
15

If x is a prime number then x+1 is not a prime number

Mathematics
2 answers:
s2008m [1.1K]4 years ago
8 0
1 come on that's seems like it but it could be three too
MissTica4 years ago
5 0
0 1 or 2 are all counter examples
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What is the exponents laws
riadik2000 [5.3K]
Laws<span> of </span>Exponents<span>. </span>Exponents<span> are also called Powers or Indices. The </span>exponent<span> of a number says how many times to use the number in a multiplication. In this example: 8</span>2<span> = 8 × 8 = 64. In words: 8</span>2<span> could be called "8 to the second power", "8 to the power 2" or simply "8 squared"</span>
6 0
3 years ago
the diameter of a pearl is about 4×10-¹⁴ cm and the diameter of an atom is about 10-¹¹ m. how much larger than an atom is a pear
serious [3.7K]

Answer:

The diameter of an atom is 25000  times the diameter of a pearl.

Step-by-step explanation:

Given that,

The diameter of a pearl is 4\times 10^{-14}\ cm

The diameter of an atom is 10^{-11}\ m=10^{-9}\ m

Taking the ratio,

\dfrac{\text{diameter of an atom}}{\text{diameter of a pearl}}=\dfrac{10^{-9}\ m}{4\times 10^{-14}\ m}\\\\=25000

So, the diameter of an atom is 25000  times the diameter of a pearl.

5 0
3 years ago
PLS HELP ITS URGENT!!
DiKsa [7]

Answer:

SA= 28 in^2

V= 14 in^3

Step-by-step explanation:

circumference= 2πr

9.4 = 2πr

r = 1.496

surface area of a ball = 4\pi r^{2}

= 4\pi (1.496)^{2}

=28 in^2

volume of a ball= \frac{4}{3} \pi r^{3}

= \frac{4}{3} \pi (1.496)^{3}

=14 in^3

5 0
3 years ago
If two rays share a common endpoint, then they will always form a line
Monica [59]
Unless they are opposite rays, then yes, they will always form a line. 
4 0
3 years ago
Determine if diverges, converges, or converges conditionally.
TEA [102]

The given series is conditionally convergent. This can be obtained by using alternating series test first and then comparing the series to the harmonic series.

<h3>Determine if diverges, converges, or converges conditionally:</h3>

Initially we need to know what Absolute convergence and Conditional convergence,

If \sum|a_{n} | → converges, and \sum a_{n} → converges, then the series is Absolute convergence

If \sum|a_{n} | → diverges, and \sum a_{n} → converges, then the series is Conditional convergence

First use alternating series test,

\lim_{k \to \infty} \frac{k^{5} +1}{k^{6}+11 } = \lim_{n \to \infty} \frac{5}{6k} = 0,

The series is a positive, decreasing sequence that converges to 0.

Next by comparing the series to harmonic series,

\sum^{\infty} _{k=2}|(-1)^{k+1} \frac{k^{5} +1}{k^{6}+11 }|=\sum^{\infty} _{k=2}\frac{k^{5} +1}{k^{6}+11 } ≈  \sum^{\infty} _{k=2}\frac{1}{k} = 0

This implies that the series is divergent by comparison to the harmonic series.

First we got that the series is converging and then we got the series is divergent. Therefore the series is conditionally convergent.

\sum|a_{n} | → diverges, and \sum a_{n} → converges, then the series is Conditional convergence.

Hence the given series is conditionally convergent.

Learn more about conditionally convergent here:

brainly.com/question/1580821

#SPJ1

7 0
2 years ago
Read 2 more answers
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