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Sloan [31]
4 years ago
8

PLEASE HURRY DOUBLE POINTS+BRAINLY my question is in the picture​

Mathematics
2 answers:
Alex17521 [72]4 years ago
5 0

Answer:

<em>Answer</em><em> </em><em>is option </em><em>b</em><em>)</em><em> </em><em>(</em><em>6</em><em>,</em><em>-5</em><em>)</em>

Step-by-step explanation:

given \: that \:  \\ centr e\: of \: circle \: is(3, - 9) \\ and \: radius \: is \: 5 \\ when \:  \:  we \: calculate \: the \: distance \: between \: (3, - 9) \: and \: (6, - 5) \\ distance \:  =  \sqrt{ {(x1 - x2)}^{2} +  {(y1 - y2)}^{2}  }  \\ here \: x1 = 3 \:  \: y1 =  - 9 \\ x2 = 6 \:  \:  \:  \: y2 =  - 5 \\ on \: substituting \: the \: values \\  =  \sqrt{(3 - 6) +  {( - 9 + 5)}^{2} }^{2 }   \\  =  \sqrt{ { - 3}^{2} +  { - 4}^{2}  }  \\  =  \\  =  \sqrt{9 + 16}  \\  =  \sqrt{25}  \\  = 5

(6 -5) is a point on the circle.

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

alisha [4.7K]4 years ago
4 0

Answer:

(6, - 5)

Step-by-step explanation:

The equation of circle in centre radius form is:

(x - h)^{2}  + (y - k)^{2}  =  {r}^{2}  \\   plugging \: h = 3 \:  \: k =  - 9 \: and \: r = 5 \\ (x - 3)^{2}  +  \{y - ( - 9) \}^{2}  =  {5}^{2}  \\  (x - 3)^{2}  +  (y  +  9)^{2}  = 25 \\ let \: us \: plug \: x = 6 \: and \: y =  - 5 \: in \: lhs \\ lhs = (6 - 3) ^{2}  + ( - 5 + 9) ^{2}  \\  =  (3) ^{2}  + ( 4) ^{2} \\  = 9 + 16 \\  = 25 \\  = rhs \\ hence \: (6, \:  \:  - 5) \: is \: on \: the \: circle.

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Answer:

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