Question

Given:An = [6 n/(-4 n + 9)]For both of the following answer blanks, decide whether the given sequence or series is convergent or divergent. If convergent, enter the limit (for a sequence) or the sum (for a series). If divergent, enter INF if it diverges to infinity, MINF if it diverges to minus infinity, or DIV otherwise.(a) The sequence {An }._________________(b) The series ∑n=1∞( An )_____________________Note: In order to get credit for this problem all answers must be correct.please show all steps. I must be makeing asilly mistake. thanks

Answer 1

Answer:

The sequence is convergent and the serie is divergent.

Step-by-step explanation:

Sequence:

We calculate the limit when n tends to infinity to see if it is convergent or divergent:

$\lim_{n \to \infty} \frac{6n}{-4n+9} = \frac{6}{-4} = \frac{-3}{2} \neq 0$ then, the sequence is convergent.

Serie:

$\sum_{n=1}^{\infty} (\frac{6n}{-4n+9})$. To know if it converges we are going to use the limit test:

$\lim_{n \to \infty} a_n$. If this limit is non equal to 0 the serie diverges.

$\lim_{n \to \infty} \frac{6n}{-4n+9} = \frac{6}{-4} = \frac{-3}{2} \neq 0$, then the serie diverges.