Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
Answer:
Step-by-step explanation:
Recall that ![\frac{x}{9}=\lfloor \frac{x}{9} \rfloor + 0.\overline{[x\:\mod9]}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B9%7D%3D%5Clfloor%20%5Cfrac%7Bx%7D%7B9%7D%20%5Crfloor%20%2B%200.%5Coverline%7B%5Bx%5C%3A%5Cmod9%5D%7D)
.
Therefore, 
.
Answer:
x=b^2+d^2/a-c
Step-by-step explanation:
Answer:
3x² - 9x + 5
Step-by-step explanation:
Given
(5x² - 3x + 4) - (2x² + 6x - 1)
Distribute the first parenthesis by 1 and the second by - 1
= 5x² - 3x + 4 - 2x² - 6x + 1 ← collect like terms
= (5x² - 2x²) + (- 3x - 6x) + (4 + 1)
= 3x² - 9x + 5
4) 10% or 1/10
5) 24% or 6/25
6) 34% or 17/50
8) 8% of 2/25
