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hichkok12 [17]
3 years ago
9

__Na + __MgF2 -> __NaF + __Mg

Chemistry
1 answer:
Scorpion4ik [409]3 years ago
6 0
There u go my friend :)

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The volume of a solid is the amount of space inside the solid? true or false
grin007 [14]
The answer is true.....
8 0
3 years ago
Convert 10 liter into m3.
stellarik [79]
0.01 cubic meters
Hope this helps
3 0
3 years ago
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4.60 mL of 0.1852 M HNO3 is titrated to the phenolphthalein indicator endpoint with 27.35 mL of a KOH solution. What is the mola
Kamila [148]

Answer:

M_{base}=0.0311M

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve for the molarity of the KOH solution by knowing this base react in a 1:1 mole ratio with nitric acid, HNO3; thus, we can write the following equation, as their moles are the same at the endpoint:

n_{acid}=n_{base}

Which in terms of molarities and volumes is:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the molarity of the base (KOH) to obtain:

M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{4.60mL*0.1852M}{27.35mL}\\\\M_{base}=0.0311M

Regards!

4 0
3 years ago
What is the energy of a photon that emits a light of frequency 6.42 x 1014 Hz?<br><br>​
svetlana [45]

Answer:

Option B. 4.25×10¯¹⁹ J

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 6.42×10¹⁴ Hz

Energy (E) =?

Energy and frequency are related by the following equation:

Energy (E) = Planck's constant (h) × frequency (f)

E = hf

With the above formula, we can obtain the energy of the photon as follow:

Frequency (f) = 6.42×10¹⁴ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =?

E = hf

E = 6.63×10¯³⁴ × 6.42×10¹⁴

E = 4.25×10¯¹⁹ J

Thus, the energy of the photon is 4.25×10¯¹⁹ J

3 0
3 years ago
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Question 1 I’m stuck on
kkurt [141]

Answer:

d

Explanation:

8 0
3 years ago
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