HELP! ONLY HAVE & MINUTES LEFT!

How much heat is required to warm 1.50L of water from 25.0C to 100.0C? (Assume a density of 1.0g/mL for the water.)

Masteriza [31]

Answer: The amount of heat required to warm given amount of water is 470.9 kJ

Explanation:

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Volume of water = 1.50 L = 1500 mL (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g$

To calculate the heat absorbed by the water, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed

m = mass of water = 1500 g

c = heat capacity of water = 4.186 J/g°C

$\Delta T$ = change in temperature = $T_2-T_1=(100-25)^oC=75^oC$

Putting values in above equation, we get:

$q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ$

Hence, the amount of heat required to warm given amount of water is 470.9 kJ

6 0

3 years ago

What are two energy alternatives to fossil fuels?

Alex17521 [72]

Explanation:

solar and energy i had to answer this one before

5 0

2 years ago

Read 2 more answers

a 25 ml volume of a sodium hydroxide solution requires 19.6 mL of a 0.189 M HCl acid for neutralization. A 10 mL volume of phosp

Drupady [299]

Answer: 0.172 M

Explanation:

a) To calculate theconcentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=0.189M\\V_1=19.6mL\\n_2=1\\M_2=?\\V_2=25mL$

Putting values in above equation, we get:

$1\times 0.189\times 19.6=1\times M_2\times 25\\\\M_2=0.148$

b) To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_3PO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?\\V_1=10mL\\n_2=1\\M_2=0.148\\V_2=34.9mL$

Putting values in above equation, we get:

$3\times M_1\times 10=1\times 0.148\times 34.9\\\\M_1=0.172M$

The concentration of the phosphoric acid solution is 1.172 M

3 0

3 years ago

The unit conversion between rankine and kelvin is (linear, exponential, quadratic, none of the above)?

diamong [38]

Answer:

Unit conversion between Rankine and Kelvin is linear.

Unit conversion between degree Celsius and degree Fahrenheit is linear.

Explanation:

Relation between rankine and Kelvin is

$R\ =\ \dfrac{9}{5}\ K$

So, the plot between Rankine and Kelvin is a straight line with zero intercept and has a slope having value $\dfrac{9}{5}$ .

Relation between degrees Celsius and degrees Fahrenheit is given by

$^{\circ}C\ =\ \dfrac{5}{9}\ (^{\circ}F\ -\ 32)$

So, the plot between degrees Celsius and degrees Fahrenheit is a straight line with slope $\dfrac{5}{9}$ and negative intercept of $\dfrac{160}{9}$ .

4 0

3 years ago

10pts Body Systems Interactions WebQuest Choose 7 out of the following 10 situations and use the Internet to research and write

GuDViN [60]

systems are involved in this process, How are they involved?
The way that you touching a hot pan and yanking your hand away is your body saying that "Aye, This isn't right" and our nerves go to the source where you had touched the hot pan... sending the signals to your brain, Your hand might have a small blister..the reason why that is, because its your bidy naturally healing its self with an internal wound

6 0

3 years ago