Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
ABC has
A as the first letter
B as the second letter
C as the third letter
The order is important
Similarly with EFG we hae
E as the first letter
F as the second letter
G as the third letter
The order is also important
Based on the orderings, we can say
A corresponds to E
B corresponds to F
C corresponds to G
Which means
A rotates to E
B rotates to F
C rotates to G
The final answer is choice C) Angle C
since we're looking for the angle that rotates or maps to angle G
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Answer:
I'd say d but if you worry choose to be then go with B
Step 1: Simplify both sides of the equation.
3(x−5)−5=23
(3)(x)+(3)(−5)+−5=23(Distribute)
3x+−15+−5=23
(3x)+(−15+−5)=23(Combine Like Terms)
3x+−20=23
3x−20=23
Step 2: Add 20 to both sides.
3x−20+20=23+20
3x=43
Step 3: Divide both sides by 3.
3x
/3 = 43
/3
x=
43
/3
