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blsea [12.9K]
3 years ago
15

What system of inequalities is graphed below?

Mathematics
2 answers:
kirill115 [55]3 years ago
5 0
y\geq x^2-4-blue\\\\y < x^2+6-red\\\\Answer:\text{I think is D.}\\y\geq x^2-4\\y < x^2+6

LenKa [72]3 years ago
5 0

Answer:

Equations are y > x² - 4 and y < x² + 6.

Step-by-step explanation:

Given : Graph with two parabola.

To find : What system of inequalities is graphed below.

Solution : We have given graph

We can see from the given graph both are dotted line that mean it does not have equal sign .

We can see graph with vertex ( 0 , -4 ) are shaded up ( grater than sign ) that mean equation would be

y > x² - 4.

For upper parabola vertex is ( 0 , 6) and shaded down( less than sign) that mean equation

y < x² + 6.

Therefore, Equations are y > x² - 4 and y < x² + 6.

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The sum of m and 188 is 232 <br><br>write the sentence as an equation ​
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Answer:

m + 188 = 232

Step-by-step explanation:

sum → +

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Just help me out with this polynomial i need help <br> { -m^{2} + 6} + { -4m^{2} + 7m + 2} =
PolarNik [594]

Answer:

-5m^2+7m+8

Step-by-step explanation:

Here, we add up two polynomials shown.

The polynomials are:

[-m^2 + 6]+[-4m^2 +7m + 2]

In order to add up the 2 polynomials shown, we have to see the "like terms" and add them up.

We add up the "m^2" terms and the constant (number) terms. There is one term with "m", so we leave it like that. Let's add up. Shown below:\

[-m^2 + 6]+[-4m^2 +7m + 2]\\=-m^2-4m^2+6+2+7m\\=-5m^2+7m+8

This is the sum of the 2 polynomials shown:  -5m^2+7m+8

7 0
3 years ago
Use cylindrical coordinates. Find the volume of the solid that lies within both the cylinder x2 + y2 = 25 and the sphere x2 + y2
Inessa05 [86]

Answer:

Step-by-step explanation:

we are asked to find the volume of solid that lies within both the cylinder

x^2 + y^2 = 25

and

the spherex^2 + y^2 + z^2 = 49.

Conversion from rectangular to cylindrical is

x=rcost\\y = rsint\\z=z

|J| =r

In cylindrical coordinates the volume is bounded by the cylinder r=5 and

r^2+z^2 =49

Hence we can write volume as

\int \int \int dxdydz\\=\\\int _0^5 \int_0^{2\pi} \int_{-\sqrt{49-r^2} } ^{\sqrt{49-r^2} rdzdtdr\\= 2\pi \int _0^5 (2\sqrt{49-r^2} rdr\\=4\pi (-(49-r^2) (2/3)\\= \frac{4\pi}{3} (343-48\sqrt{6} )

6 0
3 years ago
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