Area of triangle A/Area of triangle B = (1/3)^2
Area of triangle A/364.5 cm^2 = 1/9
Area of triangle A = 1/9×364.5cm^2
=40.5cm^2
Answer:
idk how to do this
Step-by-step explanation:
Sorry tho
Problem 1
Answer:
- The square root of the <u> expression </u> of the <u> difference </u> of <u> x^2 </u> and 11.
- The <u> quotient </u> of <u> 2 </u> times a number and -1
- The <u> sum </u> of the <u> square root </u>of two times a number and 11.
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Explanation:
The term "difference" is the result of subtraction. We're subtracting the x^2 and 11. Then applying the square root to the result.
Question 2 has the blanks filled correctly.
For the last sentence, we have a sum of the terms
and 11.
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Problem 2
Answer:
The value of an algebraic expression depends on its <u> variables </u>
- Substitute the known value for each variable.
- Simplify using the <u> order </u> of <u> operations </u>
- Use the work to answer any word problems related to the expression.
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Explanation:
The variables are placeholders for numbers
So for instance, saying x+5 is like saying "some unknown number plus 5".
We could replace it with something like x = 10 to get x+5 = 10+5 = 15
Once the variable is replaced, you use the order of operations PEMDAS (some books refer to it as BODMAS).