IF you are solving for d:
isolate the D, do the opposite of PEMDAS.
-d/6 + 12 = -7
(subtract 12 from both sides)
-d/6 + 12 (-12) = -7 (-12)
-d/6 = -19
(multiply 6 to both sides)
-d/6(6) = -19(6)
-d = -19(6)
-d = -144
-d/-1 = -144/-1
d = 144
hope this helps
A+b=100
a-b=6 ⇒ a= b+6
(b+6)+b=100
2b+6=100
2b=100-6
2b=94
b=94:2
b=47
a=47+6
a=53
Answer:
The change in the angle of elevation is approximately 63.435°
Step-by-step explanation:
The given parameters are;
The speed of the tightrope walker = 3 ft./sec
The altitude at which the tightrope walker is moving = 100 ft.
The horizontal distance of the tightrope walker from the searchlight = 200 feet
The final angle of elevation, θ, is given by the trigonometric ratio as follows;
Whereby the tightrope walker was initially vertically overhead the search light, the initial angle of elevation = 90°
The change in the angle of elevation = The initial angle of elevation - The final angle of elevation
Substituting the values gives
The change in the angle of elevation = 90° - 26.565 ≈ 63.435°
Answer:
5
Step-by-step explanation: