Let Bea = x
Therefore Andrew = x + 2
Chris = x - 3
Andrew * Chris = 66
(x + 2)(x - 3) = 66 Remove the brackets.
x^2 + 2x - 3x - 6 = 66
x^2 - x - 6 = 66 Subtract 66 from both sides.
x^2 - x - 72 = 0
(x - 9)(x + 8) = 0
Find the possible values of Bea's age
x - 9 = 0
x = 9 That value works. She can be plus 9 years old.
x + 8 = 0
x = - 8. There's no way she can be - 8 years old
So Bea is 9.
9 <<<<<< Answer
Is it radius or circumference?
Yes what do you need help with
ANSWER:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(−2,−16)
Equation Form:
x= −2, y= −16
