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3 years ago

I need help with this question.

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

5 0

A trapezoid is defined as a quadrilateral with only 1 pair of parallel sides. Since your Quadrilateral has 2 pairs, it can't be a trapezoid.

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A soccer ball is kicked toward the goal. The height of the ball is modeled by the function h(t) = −16t2 + 48t where t equals the

Stolb23 [73]

Answer:

t = 1.5; it takes 1.5 seconds to reach the maximum height and 3 seconds to fall back to the ground.

Explanation:

1) Explanation of the model:

Given: h(t) = -16t² + 48t

This is a quadratic function, so the height is modeled by a patabola.

This means that it has a vertex which is the minimum or maximu, height. Since the coefficient of the leading (quadratic) term is negative, the parabola opens downward and the vertex is the maximum height of the soccer ball.

2) Axis of symmetry:

The axis of symmetry of a parabola is the vertical line that passes through the vertex.

In the general form of the parabola, ax² + bx + c, the axis of symmetry is given by x = -b/(2a)

In our model a = - 16, and b = 48, so you get: t = - ( 48) / ( 2 × (-16) ) = 1.5

Conclusion: since t = 1.5 is the axys of symmetry, it means that at t = 1.5 the ball reachs its maximum height and that it will take the same additional time to fall back to the ground, whic is a tolal of 1. 5 s + 1.5 s = 3.0 s.

Answer: t = 1.5; it takes 1.5 seconds to reach the maximum height and 3 seconds to fall back to the ground.

8 0

3 years ago

The end of a hose was resting on the ground, pointing up an angle. Sal measured the path of the water coming out of the hose and

lawyer [7]

Functions can be used to model real life situations.

The hose is 3.2 feet above the ground, at a horizontal distance of 4 fee

The function is given as:

$f(x) =-0.3x^2 + 2x$

At a horizontal distance of 4 feet, the value of x is 4

i.e. $x = 4$

Substitute 4 for x in f(x).

So, we have:

$f(4) =-0.3(4)^2 + 2(4)$

Evaluate the exponent

$f(4) =-0.3(16) + 2(4)$

Open both brackets

$f(4) =-4.8 + 8$

Add -4.8 and 8

$f(4) =3.2$

Hence, the hose is 3.2 feet above the ground

Read more about functions at:

brainly.com/question/10837575

7 0

2 years ago

One angle of an isosceles triangle measures 96 degrees. Which other angles could be in that isosceles triangle?

Fofino [41]

One angle of an isosceles triangle measures 96 degrees. Which other angles could be in that isosceles triangle?

Ans is 42
But not sure about it

8 0

3 years ago

Write 28 1/4 as a decimal.

Naya [18.7K]

Answer:

28.25

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago