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solniwko [45]
2 years ago
7

The drama club is selling tickets to the play to raise money for the shows expenses. Each student ticket sales for five dollars

each and each adult ticket sales for $7.50 each the auditorium and hold no more than 75 people the drama club must make a minimum of $450 from ticket sales to cover the shows cost if X represents the number of students tickets sold and Y represents the number of adult tickets sold right and solve any systems of inqualities
Mathematics
1 answer:
djyliett [7]2 years ago
8 0

Answer:

45 student tickets and 30 adult tickets

Step-by-step explanation:

You can check your work by plugging both answers into both of the original equations. :)

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7 0
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Which of the below is not one of the properties of logarithms?
MrRa [10]

Answer:

option-B

Step-by-step explanation:

we know that

Sum rule of logarithm:

log(a)+log(b)=log(a\times b)

which is same as

the log of a product (ab) is equal to the addition of log a nad log b

Subtraction rule of logarithm:

log(a)-log(b)=log(\frac{a}{b} )

which is same as

the log of the quotient of a and b is equal to the log of a minus the log of b

Exponent rule of logarithm:

log(a^b)=blog(a)

which is same as

the log of the quantity a raised to b is equal to the product of b and the log of a

so,

option-B is not correct

8 0
2 years ago
Find the value of X
Blababa [14]

Answer:

should be 80, angle 50 is congruent on both sides to 50+50 equals 100. The triangle sum theorem says a triangle adds up to 180 degrees so we are left with 80, X=80 degrees

7 0
2 years ago
Read 2 more answers
One more time!
CaHeK987 [17]
Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}

so we conclude that
q(\frac{\sqrt{19} }{2} ) = 1/4

therefore

p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right)  \right)

plug x=\sqrt{19}/2 into p( q(x) ) to get answer

p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left(  \frac{\sqrt{19} }{2}\right)^2 }{ \left(  \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow

\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow  -\dfrac{6\sqrt{19} }{361}

p(1/4) = -\dfrac{6\sqrt{19} }{361}
3 0
3 years ago
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