I’m sorry, I wish I knew this one and I would help
One way would be to find the distance from the point to the center of the circle and compare it to the radius
for

the center is (h,k) and the radius is r
and the distance formula is
distance between

and

is

r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so



the radius is

center is (-2,3)
find distance between (8,4) and (-2,3)






≈4.2

≈10.04
do r<D
(8,4) is outside the circle
2.5x10^3 I think. Exponents are subtracted. The number you're multipliying by has to be more than one.
Answer:
{0, 3, 12}
Step-by-step explanation:
Put the domain values in the function and evaluate. The result is the range values.
y = 3{-2, -1, 0}^2 = 3{4, 1, 0} = {12, 3, 0}
For the given domain, the range is {0, 3, 12}.
_____
<em>Additional comment</em>
Neither the domain nor range values need to be put in any particular order. However, it is often convenient for them to be arranged from least to greatest.
Answer:
3m - 8
Step-by-step explanation:
Step by Step:
Equation= 6m³ - 16m² + 15m - 40/ 2m² + 5
Factor out 2m² from 6m³ - 16m²:
Factor out 5 from expression:
2m²(3m - 8) + 5(3m - 8)/2m² + 5
Factor out 3m - 8:
(3m - 8)(2m² + 5)/2m² + 5
Rude the fraction with 2m² + 5:
3m - 8 is the answer
I hope this helped!