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DedPeter [7]
3 years ago
15

What are the x and y- intercepts for the line 4(y+3)=−2(x+6)?

Mathematics
1 answer:
Strike441 [17]3 years ago
5 0
The x-intercept is (-12, 0)
The y-intercept is (0, -6)
Let me know if you want to see how I answered it
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Form the union in the following sets R={10, 15, 20} S={20, 25} RuS=
11111nata11111 [884]

R=\{10,15,20\}\\S=\{20,25\}\\\\R\cup S=\{10,15,20,25\}

6 0
3 years ago
Alice wanted to solve for x by getting rid if the +8. explain and correct Alice error
ra1l [238]

<u>Answer:</u> The value of x will be 2.

<u>Step-by-step explanation:</u>

To calculate the value of 'x' or solve for x, we need to isolate x from 8.

In the equation, 8 is in addition with 'x' so for isolating it, we need to apply the reverse operation of addition.

Reverse operation of addition is subtraction.

We need to subtract 8 from both sides of the equation, we get:

x+8-8=10-8\\\\x=2

By doing this, we get the value of 'x' as 2.

Error done by Alice was that she added 8 and it did not led to the isolation of 'x'.

4 0
3 years ago
Read 2 more answers
Henry can write 5 1/4 of his novel in 3 hours. how many pages can he write in eight hours
PilotLPTM [1.2K]
Henry would be able to write 14 pages of a novel in 8 hours.
5 1/4(or 5.25)/3=1 3/4 (or 1.75) 
1 3/4 x 8 =14
Hope This Helps!
~Cupcake
5 0
4 years ago
2 ACTIVITY: Estimating a Percents
Semenov [28]

Answer:

75 is 150% of 50!

3 0
2 years ago
Read 2 more answers
Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised t
zimovet [89]

Answer:

(b) 1/792

Step-by-step explanation:

The complete question is;

<em>Counting: Grading One professor grades homework by randomly choosing 5 out of 12 homework problems to grade.</em>

<em>(a) How many different groups of 5 problems can be chosen from the 12</em>

<em>problems?</em>

<em>(b)Probability extension: Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised the group that was selected to be graded?</em>

<u>In (a)</u>

<u></u>

Apply the formula

\frac{n!}{(n-r)!(r!)}

where n=12 and r=5

substitute values

=\frac{12!}{(12-5)!(5!)} \\\\\\=\frac{12!}{(7!)(5!)} \\\\\\=\frac{12*11*10*9*8}{5*4*3*2*1} \\\\\\=\frac{95040}{120} \\\\\\=792

In (b)

If Jerry did only 5 problems of one assignment then the probability  will be

\frac{5}{12} *\frac{4}{11} *\frac{3}{10} *\frac{2}{9} *\frac{1}{8} =\frac{1}{792}

<em />

<em />

4 0
3 years ago
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