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Digiron [165]
2 years ago
7

What’s the sum of c and twice d?

Mathematics
2 answers:
Damm [24]2 years ago
8 0

Answer:

The sum of c and twice d is

c + 2d

<u>-TheUnknownScientist 72</u>

Naily [24]2 years ago
4 0

Answer:

c + 2g

Step-by-step explanation:

g + g = 2g

c + 2g

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Find the slope of the line passing through the points(3,-9) and(2,-2) .
tino4ka555 [31]

Answer:

-7

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-2-(-9))/(2-3)

m=(-2+9)/-1

m=7/-1

m=-7

5 0
2 years ago
Is 0.35217534 a terminating decimal
olga_2 [115]
No, because since this decimal doesn't stop, it doesn't count as terminating
3 0
3 years ago
(20 pts)
irakobra [83]

A function can be represented by equations and tables

  • 4 users are logged in by 9am
  • The domain is [3,23] and the range of the function is [3,4]

<h3>The number of users at 9am</h3>

The function is given as:

g(x) = \frac14 \sqrt{x - 3} + 3

At 9am, x = 9.

So, we have:

g(x) = \frac14 \sqrt{9 - 3} + 3

g(x) = \frac14 \sqrt{6} + 3

Simplify

g(9) = 3.6

Approximate

g(9) = 4

Hence, 4 users are logged in by 9am

<h3>The domain</h3>

Set the radical to 0

x - 3 = 0

Solve for x

x = 3

The maximum time after midnight is 23 hours.

So, the domain is [3,23]

<h3>The range</h3>

When x = 3, we have:

g(x) = \frac14 \sqrt{x - 3} + 3

g(3) = \frac 14 * \sqrt{3 - 3} + 3 = 3

When x = 23, we have:

g(23) = \frac 14 * \sqrt{23 - 3} + 3 = 4

So, the range of the function is [3,4]

Read more about domain and range at:

brainly.com/question/2264373

3 0
2 years ago
2/9 x 45<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B9%7D%20%2A%2045%5C%5C" id="TexFormula1" title="\frac{2}{9} * 45\
Tcecarenko [31]

Answer:

Divide X^2-14x+45 by x-9

Step-by-step explanation:

im just trying to get free points

3 0
3 years ago
Plz help me I need so much help
WINSTONCH [101]

Answer:

  see below

Step-by-step explanation:

We have to assume that the question is referring to the doubly-shaded length, the one that is 10 bright blue units long.

You can read the overall length of the shaded area as 5/4, from the markings.

For the next part, you need to count the number of units that are shaded bright blue (10) and the number that are shaded blue overall (15). As a fraction of those shaded blue overall, the ones shaded bright blue are 10/15 = 2/3.

So, the length shaded bright blue is 2/3 of the overall length of 5/4. It is represented by the product ...

  \boxed{\dfrac{2}{3}\times\dfrac{5}{4}}

7 0
3 years ago
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