To solve for this, we need to find for the value of x
when the 1st derivative of the equation is equal to zero (or at the
extrema point).
So what we have to do first is to derive the given
equation:
f (x) = x^2 + 4 x – 31
Taking the first derivative f’ (x):
f’ (x) = 2 x + 4
Setting f’ (x) = 0 and find for x:
2 x + 4 = 0
x = - 2
Therefore the value of a is:
a = f (-2)
a = (-2)^2 + 4 (-2) – 31
a = 4 – 8 – 31
a = - 35
Answer:
<h2>x = 3</h2>
Step-by-step explanation:
<h2>
Put x = 
I write the sum of 6x and 2x is at least 39 .</h2>
Step-by-step explanation:
We have,,
6x and 2x
To find, the value of x = ?
According to question,
The sum of 6x and 2x is at least 39
∴ 6x + 2x = 39
⇒ 8x = 39
⇒ x =
∴ The value of x =
Thus, put x = I write the sum of 6x and 2x is at least 39 .
Answer: your mom gay ;)
Step-by-step explanation:
4,500 calories a day
If you ate the same amount each day, that means you would eat 3 a day, since 6 divided by 2 is 3.
Find how many calories you would eat each day by multiplying 3 by 1,500
3(1,500)
= 4500
Answer: x=7.5
Step-by-step explanation:
