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svp [43]
4 years ago
13

Harvey the wonder hamster can run 3 1/6 km in 1/4 hour find his average speed in kilometers pe hour

Mathematics
2 answers:
iren2701 [21]4 years ago
6 0

there are 4 quarters to 1 hour

3 1/6 x 4 =

19/6 * 4 = 76/6 = 12 4/6, reduces to 12 2/3 km per hour

kkurt [141]4 years ago
5 0

Answer:- The average speed of Harvey the wonder hamster is12\frac{2}{3}\ km/hour.


Explanation:-

Given: Distance traveled by Harvey =3\frac{1}{6}\ km=\frac{19}{6}\ km

Time taken=\frac{1}{4}\ hour

Speed=\frac{Distance}{Time}\\\Rightarrow\ Speed=\frac{\frac{19}{6}}{\frac{1}{4}}\\\\=\frac{19\times4}{6}\\\\=\frac{38}{ 3}\\\\=12\frac{2}{3}\ km/hour

Therefore, the average speed of Harvey the wonder hamster is12\frac{2}{3}\ km/hour.

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A baseball player got 102 hits in the last 300 times at bat. Explain how you would find the percent of times at bat.​
slava [35]

Answer:

34%

Step-by-step explanation:

Divide the number of hits, 102, by the times at bat, 300. Then move the decimal 2 places to the right and add the percent sign to get 34%.

6 0
3 years ago
Read 2 more answers
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,564 miles, with a standard
DerKrebs [107]

Answer:

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{48101 - 48564}{196.44}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

6 0
3 years ago
Which linear inequality is represented by the graph?
Tamiku [17]

Answer:

Option (4)

Step-by-step explanation:

From the graph attached,

A dotted line passes through two points (3, 1) and (-3, -3)

Let the equation of the given line is,

y = mx + b

where 'm' = slope of the line

b = y-intercept

Slope of a line passing through (x_1, y_1) and (x_2,y_2) is,

m = \frac{y_2-y_1}{x_2-x_1}

For the given points,

m = \frac{1+3}{3+3}

m = \frac{2}{3}

y-intercept 'b' = -1

Therefore, equation of the given line will be,

y=\frac{2}{3}x-1

Since graphed line is a dotted line so it's representing an inequality(having < or > sign)

And the shaded part is below the dotted line,

Inequality will be,

y < \frac{2}{3}x-1

Therefore, Option (4) will be the answer.

7 0
3 years ago
Ethan jogged 1 1/3 miles. Chloe jogged 1 1/4 times as far as Ethan. How many miles did Chloe jog?
Paul [167]
<span>Ethan jogged 1 1/3 miles. Chloe jogged 1 1/4 times as far as Ethan. How many miles did Chloe jog?
2.7miles</span>
3 0
3 years ago
Answer please VVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVV
mezya [45]

\left[\begin{array}{ccc}3 & 9 \\\\ 5& -2\end{array}\right]+\left[\begin{array}{ccc}6 & 0\\\\ \!\!-8 & 4\end{array}\right]=\left[\begin{array}{ccc} 3+6 & 9+0 \\\\5-8 &-2+4 \end{array}\right] =\left[\begin{array}{ccc} 9& 9 \\\\ -3 & 2\end{array}\right]

6 0
2 years ago
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