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olga55 [171]
2 years ago
8

How to figúrate out if x makes the equation true

Mathematics
2 answers:
marissa [1.9K]2 years ago
7 0
You plug in the number for x and if it is equal to the solution then it is correct
fomenos2 years ago
7 0

Answer:

Someone already explained this and their right but I wanted to add an example.

Lets say you have the equation 4x+3=19.

You solve it by subtracting three from both sides to isolate x which gives you 4x=16 and dividing both sides by 4 to get you an answer of 4.

Now, you know x=4 but you're not completely sure so you can check it.

Substitute the known value of x into the original equation and check to see if both sides equal.

4(4)+3=19

16+3=19

19=19

This checks out so your answer is correct.

You might be interested in
Four times a number added to 3 times a larger number is 31. Seven subtracted from the larger number is equal to twice the smalle
notka56 [123]

Answer:

Let x represent the smaller number and y represent the larger number

<u>For the first equation </u>

Four times a number added to 3 times a larger number is 31 is written as

4x + 3y = 31

Making y the subject we have

3y = - 4x + 31

Divide both sides by 3

That's

y =  -  \frac{4}{3} x +  \frac{31}{3}

<u>For the second equation</u>

Seven subtracted from the larger number is equal to twice the smaller number is written as

y - 7 = 2x

Making y the subject

We have

<h3>y = 2x + 7</h3>

Hope this helps you

7 0
3 years ago
Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24
S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

\frac{4}{3}=\frac{32}{d}

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable d and see if it satisfies the equation.

1) d=22

\frac{4}{3}=\frac{32}{22}

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 2}{22\div 2}

\frac{4}{3}=\frac{16}{11}

The above statement can never be true and hence 22 is not a solution.

2) d=23

\frac{4}{3}=\frac{32}{23}

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

3) d=24

\frac{4}{3}=\frac{32}{24}

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 8}{24\div 8}

\frac{4}{3}=\frac{4}{3}

The above statement is always true and hence 24 is a solution.

4) d=25

\frac{4}{3}=\frac{32}{25}

The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

4 0
2 years ago
Slope intercept of (1,1) and (0,7)
Sonja [21]

Answer:

\boxed {m = -6}

Step-by-step explanation:

Use the <u>Slope Formula</u> to help you determine the slope of the following two points:

m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}

(Where (x_{1}, y_{1}) is the first point and (x_{2}, y_{2}) is the second point)

-Apply both points onto that formula:

(x_{1}, y_{1}) = (1, 1)

(x_{2}, y_{2}) = (0, 7)

m = \frac{7 - 1}{0 - 1}

-Solve:

m = \frac{7 - 1}{0 - 1}

m = \frac{6}{-1}

\boxed {m = -6}

3 0
2 years ago
A quadratic equation has zero real number solutions. Which could be the discriminant value associated with this equation?
andriy [413]
It will be -5 I pretty sure but I’m not sure
8 0
3 years ago
A rhombus with congruent sides is shown. Diagonals are drawn. The length of one diagonal is 6, and the length of the other diago
dezoksy [38]

Answer:

its 24

Step-by-step explanation:

i got it right on ed 2020

8 0
3 years ago
Read 2 more answers
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