Here's a rough graph haha
the graph has a factor of 4/1 (considered the "slope"), and the vertex is translated 2 units to the right (whatever is in the | lines | has the negative/positive flipped), and 6 units down.
(d): y = mx+n
m = -2/3 ⇒ y = (-2/3)x +n
A(-4, 6) ∈ d ⇒ 6 = (-2/3)·(-4) +n ⇒ 6 = 8/3 +n ⇒
⇒ n = 6 - 8/3 ⇒ n = 10/3
Now, we have:
y = (-2/3)x +10/3
Answer:
Probability that detector B goes off is '0.615'
Step-by-step explanation:
Given that:
1) Probability that detector A goes off and detector B does not go off is 0.25.
2)Probability that detector A does not go off is 0.35.
3)Probability that detector A goes off is (1-0.35)=0.65
Assuming that
Probability that detector B goes off is 'p' Hence the probability that detector B does not goes off is (1-p)
Thus the probability that detector A goes off and detector B does not go off is product of the individual probabilities
Probability that detector B goes off is '0.615'
Can’t read the paper sry try again please
