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Debora [2.8K]
3 years ago
8

You’re repairing a large rectangular aquarium. The final step is to cover the glass with a protective film. The front and back o

f the aquarium measure 4 meters by 2 meters, and the sides of the aquarium measure 3 meters by 2 meters. How many square meters of protective film do you need?
Mathematics
2 answers:
Marianna [84]3 years ago
6 0

Answer:

28 square metres

Step-by-step explanation:

Calculate the total surface area of the glass covered part of the rectangular aquarium

Surface area = 2(4 × 2) + 2(3 × 2)

= 16 + 12

Protective film needed = 28 square metres

dangina [55]3 years ago
3 0

Answer: Area of protective film would be 28 m².

Step-by-step explanation:

Since we have given that

Dimensions of front and back of the aquarium is given by

4 meters by 2 meters

Dimensions of sides of the aquarium is given by

3 meters by 2 meters.

So, Area of protective film he needed is given by

2(4\times 2)+2(3\times 2)\\\\=2\times 8+2\times 6\\\\=16+12\\\\=28\ m^2

Hence, Area of protective film would be 28 m².

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240 percent

Step-by-step explanation:

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3 years ago
What is 215% of 44? 9460 946 94.6 9.46
nirvana33 [79]

Answer:

94.6

Step-by-step explanation:

     100% of 44 = 44

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How does tripling the side lengths of a right triangle affect its area?)
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3 years ago
Read 2 more answers
What Expression is equivalent to -3(2m-1)-n​
denis-greek [22]

Answer:

-6m+3-n

Step-by-step explanation:

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3 years ago
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Anna71 [15]

Answer:

  a) positive real zeros: 2 or 0; negative real zeros: 2 or 0; complex zeros: 0, 2, or 4. (rule of signs)

  b) ∪-shaped, as for an even-degree polynomial with positive leading coefficient. See attached.

  c, d) See attached

Step-by-step explanation:

Descarte's rule of signs gives bounds on the number of positive and negative real roots. The numbers it gives may be reduced by multiples of 2, as complex roots will come in conjugate pairs. The total number of roots of all kinds will match the degree of the polynomial.

Synthetic division is essentially polynomial long division with some modifications:

  • the variables are omitted ("place value" is used instead)
  • the constant in the divisor is <em>negated</em> so its product with the partial quotient can be <em>added</em> to obtain the new dividend
  • the divisor binomial is assumed to have a leading coefficient of 1.

__

<h3>a) </h3>

The signs of the terms of the given polynomial are + - - - +. There are two sign changes, so 2 possible positive real roots.

When the signs of the odd-degree terms are changed, the signs become + + - + +. There are still two sign changes, so 2 possible negative real roots.

Either or both of these numbers can be reduced by 2 if the roots include a conjugate pair. That is, there may also be 0 possible positive real roots, and 0 possible negative real roots.

The number of non-real (complex) zeros may be any multiple of 2 up to the degree of the polynomial. The may be 0, 2, or 4 possible non-real zeros.

__

<h3>b)</h3>

The graph is the first attachment. It shows 4 real zeros: x = -4, -2, 1, 6.

Since the polynomial is of even degree (4) and has a positive leading coefficient (+1), we expect the general shape to be ∪-shaped. It is.

__

<h3>c)</h3>

The second attachment shows synthetic division using x = -4. (The binomial divisor is (x+4).) The remainder (lower right value in the tableau) is the value of y when x=-4. The third attachment shows synthetic division using the value x=3. (y is -210 when x=3.)

Maybe this is the table you want:

  \begin{array}{|c|c|c|}\cline{1-3}x&-4&3\\\cline{1-3}y&0&-210\\\cline{1-3}\end{array}

__

<h3>d)</h3>

The second attachment shows synthetic division by the factor (x+4).

_____

<em>Additional comment</em>

The synthetic division attachments show instructions for carrying out the synthetic division and interpreting the results. As we said above, "the entry on the left" is the opposite of the constant in the binomial divisor. It is the actual value of x you want to use to evaluate the function.

The equations shown are merely for the purpose of indicating the operations that are used. An actual synthetic division tableau is simply a 3-row table of numbers, with the bottom row being the quotient coefficients and remainder.

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