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In-s [12.5K]
3 years ago
5

Explain in at least 5 sentences why scientific notation is important. You can choose a job or company that would use it and give

examples or just explain. Make sure to write in at least 5 complete sentences!
Mathematics
1 answer:
Lana71 [14]3 years ago
8 0

Answer:

UwU

Step-by-step explanation:

UwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwUUwU

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Find the area of shaded region.
Rudiy27

Hey there mate ;),

Area of The shades region is <u>3098 m^2</u>

The solution is attached as picture. Please check.

<em>Answered</em><em> </em><em>by</em><em> </em><em>Benjemin</em>

6 0
2 years ago
Whats the sqareroot of 33
andre [41]

Answer:

5.744

Step-by-step explanation:

the answer is 5.744 hope it helps!

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Words to know Match each word to know with its definition. dividend the number a dividend is divided by in a division problem di
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3 years ago
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41.3+0.7 adding and subtracting decimals
viktelen [127]
The answer would be 42
Because the 0.3 (from the number 41.3) and 0.7 make 1 so basically it would be 41+1=42
(Sorry if wrong! Mark brainiest if right!)
8 0
3 years ago
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A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic
Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are​ defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are​ defective?

Solution:

Let the random variable <em>X</em> represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.

A random sample of <em>n</em> = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.

The probability mass function of <em>X</em> is:

P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...

Compute the probability that none of the LED light bulbs are​ defective as follows:

P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}

                =1\times 1\times 0.737424\\=0.737424\\\approx 0.7374

Thus, the probability that none of the LED light bulbs are​ defective is 0.7374.

6 0
3 years ago
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