All categories

3 years ago

CUCU

Mathematics

1 answer:

puteri [66]3 years ago

6 0

Answer:

Step-by-step explanation:

well, the sequence are in the form

$a1, a2, a3, a4, a5, ... , an$

a1 = first term = 45

you can plug 1 to any of the option

and ended with B the only function that satisfies what we need

You might be interested in

What is the slope of the equation: x = -2

Harrizon [31]

Answer:

undefined

Step-by-step explanation

it is a vertical line and has no defined slope

5 0

4 years ago

Use limits to find the area of the region bounded by the graph f(x)=4-2x^3 , the x-axis , and the vertical lines x=0 and x=1

gtnhenbr [62]

Answer:

$\frac{7}{2}$ square units.

Step-by-step explanation:

We have to use limits to find the area of the region bounded by the graph $f(x) = 4 - 2x^{3}$ , the x-axis, and the vertical lines x=0 and x=1.

So, the area will be

A = $\int\limits^1_0 {(4 - 2x^{3})} \, dx$

= $[4x - \frac{x^{4}}{2} ]^{1} _{0}$

= $4 - \frac{1}{2}$

= $\frac{7}{2}$ square units. (Answer)

3 0

4 years ago

What is the equation for a line that passes through the points (5,-4) and (-10,17

maria [59]

Answer:

The equation of the line is 7 x +5 y = 15.

Step-by-step explanation:

Here the given points are ( 5, -4) & ( -10, 17) -

Equation of a line whose points are given such that

( $x_{1},y_{1}$ ) & ( $x_{2}, y_{2}$ )-

y - $y_{1}$ = $\frac{y_{2} - y_{1} }{x_{2} - x_{1}}$ ( x - $x_{1}$ )

i.e. y - (-4)= $\frac{17 - (-4)}{-10 - 5}$ ( x- 5)

y + 4 = $\frac{17 + 4}{ -15}$ ( x - 5)

y + 4 = $\frac{21}{-15}$ ( x - 5 )

( y + 4) = $\frac{7}{- 5}$ ( x - 5)

5 (y + 4 ) = - 7 (x - 5 )

5 y + 20 = -7 x + 35

7 x + 5 y = 15

Hence the equation of the required line whose passes trough the points ( 5, -4) & ( -10, 17) is 7 x + 5 y = 15.

7 0

3 years ago

1) Nat's grocery bill was $150, which included a 5% club

a_sh-v [17]

Answer:

$157.89

Step-by-step explanation:

you could say that 150 is 95% of what the original bill was

in equation form: 150 = .95x

150/.95 = 158.89

158.89 = x

3 0

2 years ago

Read 2 more answers

Suppose a football player kicks a ball and gives it an initial upward velocity of 47 ft/s. Use the formula h(t)= -16t^2+47t+3 wh

statuscvo [17]

Answer:

Step-by-step explanation:

a. when t=0,h=3ft

$h(t)=-16 (t^2-\frac{47}{16}x+(\frac{47}{32} )^2)+\frac{47^2}{32^2} *16+3\\=-16(t-\frac{47}{32})^2+\frac{2209}{64}+3\\=-16(t-\frac{47}{32})^2+\frac{2209+192}{64}\\when~ t=\frac{47}{32}\\h=\frac{2301}{64}\\or~v^2-u^2=2gh\\\\0^2-47^2=2*(-32)h\\or h=\frac{47^2}{64}=\frac{2209}{64} \\height from the ground=\frac{2209}{64} +3=\frac{2301}{64}$

c.t=47/32 sec

time taken to fall 2301/64 ft=0*t+\frac{1}{2}*32*t^2

t^2=\frac{2301}{64*16}

t=\frac{\sqrt{2301}}{8*4}=\frac {47.97}{32}

total ~time=\frac{47+47.97}{32}=\frac{94.97}{32} sec

4 0

3 years ago