2 years ago

CUCU

Mathematics

1 answer:

puteri [66]2 years ago

6 0

Answer:

Step-by-step explanation:

well, the sequence are in the form

$a1, a2, a3, a4, a5, ... , an$

a1 = first term = 45

you can plug 1 to any of the option

and ended with B the only function that satisfies what we need

You might be interested in

In the diagram, line p is parallel to line q. <br> What is the value of x and y?<br> (NEED HELP)

hichkok12 [17]

Y is 42°

The x is not the picture

4 0

2 years ago

(PLEASE HELP)

ddd [48]

Answer:

A.less than 6 but more than 20

4 0

2 years ago

There are 800 bags of beans. Each bag contains 20,000 beans. How many beans are there in all?

Zepler [3.9K]

Answer: 16,000,000

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which of the following graphs is the solution set of -10 < 3x - 4<8?

TEA [102]

Answer:

The third one

Step-by-step explanation:

The image above is the explanation, hopefully its help

5 0

2 years ago

In Exercises 3–10, use the Chain Rule to calculate the partial derivatives. Express the answer in terms of the independent varia

sashaice [31]

I'll use subscript notation for brevity, i.e.

$\dfrac{\partial f}{\partial x}=f_x$

$f(x,y,z)=xy+z^2\implies\begin{cases}f_x=y\\f_y=x\\f_z=2z\end{cases}$

$x(r,s)=s^2\implies\begin{cases}x_r=0\\x_s=2s\end{cases}$

$y(r,s)=2rs\implies\begin{cases}y_r=2s\\y_s=2r\end{cases}$

$z(r,s)=r^2\implies\begin{cases}z_r=2r\\z_s=0\end{cases}$

By the chain rule,

$f_r=f_xx_r+f_yy_r+f_zz_r=2xs+4zr=2s^3+4r^3$

$f_s=f_xx_s+f_yy_s+f_zz_s=2ys+2xr=6rs^2$

$x(r,s,t)=r+s-2t\implies\begin{cases}x_r=1\\x_s=1\\x_t=-2\end{cases}$

$y(r,s,t)=3rt\implies\begin{cases}y_r=3t\\y_s=0\\y_t=3r\end{cases}$

$z(r,s,t)=s^2\implies\begin{cases}z_r=0\\z_s=2s\\z_t=0\end{cases}$

By the chain rule,

$f_r=f_xx_r+f_yy_r+f_zz_r=y+3xt=3rt+3r+3s-6t^2$

$f_s=f_xx_s+f_yy_s+f_zz_s=y+4zs=3rt+4s^3$

$f_t=f_xx_t+f_yy_t+f_zz_t=-2y+3xr=3r+3s-12rt$

8 0

2 years ago