First you have to figure out the length of the track:
![2 * \pi * r](https://tex.z-dn.net/?f=%202%20%2A%20%5Cpi%20%2A%20r%20)
r is the half of the diameter:
200ft : 2 = 100ft
![2* \pi *100ft](https://tex.z-dn.net/?f=%202%2A%20%5Cpi%20%2A100ft%20)
= 200
![\pi](https://tex.z-dn.net/?f=%20%5Cpi%20)
≈
628,31
The athlete has to run ca. 5280ft for one mile:
5280 : 628,31≈8,4
The athlete has to run 8,4 laps
Answer:
D. 16
Step-by-step explanation:
Do the division first
-16 ÷ (-4) = 4 then do the sum
12 + 4 = 16
Answer:
11 33/35
Step-by-step explanation:
5 3/7 = 5 × 7/7 + 3/7 = 35 + 37 = 38/7
38/7 ÷ 5/11 = 38/7 × 11/5 = 38 × 11/7 × 5 = 418/35
418/35 = 11 33/35
Hope this helps!
if we take £15837.77 to be the 100% and we increase it by 18.5%, that'll be 100% + 18.5% = 118.5%.
![\begin{array}{ccll} \pounds&\%\\ \cline{1-2} 15837.77 & 100\\ x& 118.5 \end{array} \implies \cfrac{15837.77}{x}=\cfrac{100}{118.5} \implies (15837.77)(118.5)=100x \\\\\\ \cfrac{(15837.77)(118.5)}{100}=x\implies 18767.76\approx x](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccll%7D%20%5Cpounds%26%5C%25%5C%5C%20%5Ccline%7B1-2%7D%2015837.77%20%26%20100%5C%5C%20x%26%20118.5%20%5Cend%7Barray%7D%20%5Cimplies%20%5Ccfrac%7B15837.77%7D%7Bx%7D%3D%5Ccfrac%7B100%7D%7B118.5%7D%20%5Cimplies%20%2815837.77%29%28118.5%29%3D100x%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B%2815837.77%29%28118.5%29%7D%7B100%7D%3Dx%5Cimplies%2018767.76%5Capprox%20x)