<span>flying to kampala with a tailwind a plane averaged 158 km/h. on the return trip the plane only averaged 112 km/h while flying back into the same wind. find the speed of the wind and the speed of the plane instill air. -------------------------------- Let plane speed be "p". Let wind speed be "w". --------- Equations: p + w = 158 p - w = ...</span><span>
</span>
Answer: Each bow needs 4.67 yards of ribbon.
Step-by-step explanation:
We know that each roll has 20 yd.
She used 3 + 1/2 rolls, then the total length used will be (3 + 1/2) times the length of each roll, this is:
(3 + 1/2)*20 yd = (6/2 + 1/2)*20yd = (7/2)*20yd = 70 yd.
With tose 70 yards of ribbon, she made 15 bows, then the length of ribbon used in each bow will be equal to the quotient between the total length used and the number of ribbons made with it, this is:
70yd/15 = 4.67 yards
Each bow needs 4.67 yards of ribbon.
Answer:
22°
Step-by-step explanation:
sin(theta)=7/19
m(theta)= arcsin(7/19)=22°
Hey 4:3 is an equal ration to 20:15
The general form of the given equation is 2x+y-6 = 0.
<u>Step-by-step explanation</u>:
- The given linear equation is 2x+y=6.
- The general form of the equation is AX+BY+C=0.
where,
- A is the co-efficient of x.
- B is the co-efficient of y.
- C is the constant term.
<u>From the given equation 2x+y=6, it can be determined that</u> :
The co-efficient of x is 2. It is in the form AX = 2x. Thus, no change is needed.
The co-efficient of y is 2. It is in the form BY = 1y. Thus, no change is needed.
The constant term 6 should be replaced to the left side of the equation, since the right side of the equation must be 0 always.
While moving the constant term form one side of the equation to other side, the sign changes from +ve to -ve.
Therefore, the general form is given as 2x+y-6 = 0.
