Answer:
x = 4
y = -3
Step-by-step explanation:
We can use substitution, elimination, or graphically.
Step 1: Rearrange first equation
2x + 4y = -4
2x = -4 - 4y
x = -2 - 2y
Step 2: Rewrite systems of equations
x = -2 - 2y
3x + 5y = -3
Step 3: Substitution
3(-2 - 2y) + 5y = -3
-6 - 6y + 5y = -3
-6 - y = -3
-y = 3
y = -3
Step 4: Find <em>x</em> using <em>y</em>
2x + 4(-3) = -4
2x - 12 = -4
2x = 8
x = 4
Graphically:
Use a graphing calc and analyze where the 2 lines intersect.
I am stuck on same thing as u
Step-by-step explanation:
6square root of 3 (numerator) over÷ square root of 3 and square root of 3. Then you get 6 square root of 3 over ÷ 3=2 square root of 3.
Take time mate) Good day.
Answer:
- 3 or 1 positive real zeros
- 0 negative real zeros
Step-by-step explanation:
The signs of the coefficients of the given terms are ...
+ - + -
There are three sign changes, so the number of positive real zeros is 3 or 1.
When odd-degree terms have their signs changed, the signs become ...
- - - -
There are no sign changes, hence no negative real zeros.
_____
A graph confirms this evaluation.
Answer: (x+2)*(x-4)*(x+21) = 0 has "many" solutions
Step-by-step explanation: (x+2) = 0 only has one solution.
(x+2)*(x-4) = 0 has two solutions, -2 and 4
(x+2)*(x-4)*(x+21) = 0 has three solutions, -2, 4, and -21, etc
If "many" means more than three, then add another (x+XX) term. A quadratic equation generally has two solutions.
