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Sedaia [141]
3 years ago
5

(1) who ever gets this right will get a brainlest

Mathematics
2 answers:
kirill [66]3 years ago
8 0

Answer:

$50.85

I hope this helped. If you need an explanation:

45/100*113

=1017/20 which is also equal to 50.85

kicyunya [14]3 years ago
3 0
$50.85 just need the points
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How do you solve this system of equation?<br> 2x+4y=-4<br> 3x + 5y =-3
Annette [7]

Answer:

x = 4

y = -3

Step-by-step explanation:

We can use substitution, elimination, or graphically.

Step 1: Rearrange first equation

2x + 4y = -4

2x = -4 - 4y

x = -2 - 2y

Step 2: Rewrite systems of equations

x = -2 - 2y

3x + 5y = -3

Step 3: Substitution

3(-2 - 2y) + 5y = -3

-6 - 6y + 5y = -3

-6 - y = -3

-y = 3

y = -3

Step 4: Find <em>x</em> using <em>y</em>

2x + 4(-3) = -4

2x - 12 = -4

2x = 8

x = 4

Graphically:

Use a graphing calc and analyze where the 2 lines intersect.

5 0
3 years ago
Please help me on this question
viva [34]

I am stuck on same thing as u

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How to simplify this equation
Ainat [17]
6square root of 3 (numerator) over÷ square root of 3 and square root of 3. Then you get 6 square root of 3 over ÷ 3=2 square root of 3.
Take time mate) Good day.
6 0
3 years ago
What does​ Descartes' rule of signs tell you about the possible number of positive real zeros and the possible number of negativ
Sergio039 [100]

Answer:

  • 3 or 1 positive real zeros
  • 0 negative real zeros

Step-by-step explanation:

The signs of the coefficients of the given terms are ...

  +  -  +  -

There are three sign changes, so the number of positive real zeros is 3 or 1.

When odd-degree terms have their signs changed, the signs become ...

  -  -  -  -

There are no sign changes, hence no negative real zeros.

_____

A graph confirms this evaluation.

8 0
3 years ago
Help quick please give an explanation too.
Lady_Fox [76]

Answer: (x+2)*(x-4)*(x+21) = 0 has "many" solutions

Step-by-step explanation: (x+2) = 0 only has one solution.  

(x+2)*(x-4) = 0 has two solutions, -2 and 4

(x+2)*(x-4)*(x+21) = 0 has three solutions, -2, 4, and -21, etc

If "many" means more than three, then add another (x+XX) term.  A quadratic equation generally has two solutions.

4 0
3 years ago
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