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Irina-Kira [14]
4 years ago
15

F(x) = x; translation

Mathematics
1 answer:
tatyana61 [14]4 years ago
8 0

Answer:

the transformed function becomes: g(x) = 5 x - 30

Step-by-step explanation:

When the function f(x) = x is shifted down by a factor of 6 we have the following transformation:

f(x) --> x - 6

After this, a vertical stretch by a factor of 5 should affect the full functional expression in the following way:

5 ( x - 6) = 5 x - 30

Therefore the transformed function becomes: g(x) = 5 x - 30

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Assume the upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.3 centimeters (
oksian1 [2.3K]

Answer:

a) For this case we can use this:

P(X

P(X>\mu +3*\sigma)=P(X>46.5)=0.0015

So the range of lengths would be 32.1 and 46.5 since on the middle of these two values we have 1-0.0015-0.0015=0.997 or 99.7 % of the values.

b) P(X>36.9)

And using the complement rule we have:

P(X>36.9)= 1-P(X

Step-by-step explanation:

Previous concepts

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

Let X the random variable who represent the variable of interest.

From the problem we have the mean and the standard deviation for the random variable X. E(X)=39.3, Sd(X)=2.4

So we can assume \mu=39.3 , \sigma=2.4

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

So we have the following probabilities using this rule:

P(X    

P(X>\mu +\sigma)=P(X >41.7)=0.16  

P(X    

P(X>\mu +2*\sigma)P(X>44.1)=0.025

P(X

P(X>\mu +3*\sigma)=P(X>46.5)=0.0015

Part a

For this case we can use this:

P(X

P(X>\mu +3*\sigma)=P(X>46.5)=0.0015

So the range of lengths would be 32.1 and 46.5 since on the middle of these two values we have 1-0.0015-0.0015=0.997 or 99.7 % of the values.

Part b

For this casee we want this probability:

P(X>36.9)

And using the complement rule we have:

P(X>36.9)= 1-P(X

5 0
3 years ago
The graph of a function f is shown below.<br> Find f(0).
lesantik [10]

Answer: f(0)=-1

Step-by-step explanation:

f(0) is a fancy way of saying the y value of the equation. the f(0) means that x=0. If you look at x=0, the graph is at y=-1. Therefore, f(0)=-1.

4 0
3 years ago
Read 2 more answers
). The length and width of a room are in the ratio 5 to 7.
natima [27]

Answer:

65

Step-by-step explanation:

6 0
3 years ago
Write a real world problem for 8x=48
Evgen [1.6K]

Answer:

the total number of profits made at the fair was $48. each person had to pay $8 to get in. how many people were at the fair

Step-by-step explanation:

8 0
3 years ago
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
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