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ale4655 [162]
3 years ago
15

At t= 0, a particle starts from rest at x= 0, y = 0, and moves in the xy plane with an acceleration a⃗ = (4.0i^ + 3.0j^)m/s2. As

sume t is in seconds. Determine the speed of the particle as a function of time t.
Mathematics
1 answer:
TEA [102]3 years ago
3 0
Because the initial conditions are zero, one integrates twice, discarding the constant of integration each time. The displacement vector, s(t), is: 
<span>s(t) = (2.0î + 1.5ĵ)t² meters</span>
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Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours of production time
user100 [1]

The question is incomplete, here is the complete question

Recall the production model from Section 1.3:

Max 10x

s.t. 5x ≤ 40

x ≥ 0

Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours for each unit produced. Assume total production capacity remains 40 units. Use y as the number of units of product 2 produced. . Show the mathematical model when both products are considered simultaneously.

Answer:

Max Profit: 10x + 5y

5x + 2y ≤ 40

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Explanation:

x= number of units of product 1 produced

y = number of units of product 2 produced

Since the first product, x, has a unit profit of $10 and Max1 is 10x

Second product, y, has a unit profit of $5, Max2 = 5y

The maximum profit when both products are considered simultaneously is 10x + 5y

Max Profit = 10x + 5y

Time required for each unit of x is 5hours

Therefore, time required for x units is 5x hours

Time required for each unit of y is 2hours  

Therefore, time required for y units is 2y hours

Time required for the simultaneous production of both products is 5x + 2y

Since production capacity remains 40 units, 5x+2y ≤40

NB: The values of x and y cannot be negative  

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