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Karo-lina-s [1.5K]
3 years ago
15

True or False? A circle could be circumscribed about the quadrilateral below.

Mathematics
1 answer:
pogonyaev3 years ago
6 0

Answer:true

Step-by-step explanation:

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All the factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.<br><br><br> True or False
Gekata [30.6K]
Factors of 48 are 1,2,3,4,6,8,12,16,24,48.

True.
6 0
3 years ago
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What is the value of this expression?<br> 5x (8 – 3) + 2
ivolga24 [154]

Answer:

27

Step-by-step explanation:

5 x (8 - 3) +2

5 x (5) + 2

25 + 2

27

Hope that helps!

4 0
3 years ago
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Which expression is equal to 4 x 3 x 5?
kupik [55]

Answer:

60

Step-by-step explanation:

Step 1: Write expression

4 × 3 × 5

Step 2: Multiply

12 × 5

60

3 0
3 years ago
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Name a pair of corresponding angles
Gnoma [55]
<h3>Corresponding angles = angle 1 and angle 5</h3>

They are on the same side of the transversal cut (both to the left of the transversal) and they are both above the two black lines. It might help to make those two black lines to be parallel, though this is optional.

Other pairs of corresponding angles could be:

  • angle 2 and angle 6
  • angle 3 and angle 7
  • angle 4 and angle 8

=======================================================

<h3>Alternate interior angles = angle 3 and angle 5</h3>

They are between the black lines, so they are interior angles. They are on alternate sides of the blue transversal, making them alternate interior angles.

The other pair of alternate interior angles is angle 4 and angle 6.

=======================================================

<h3>Alternate exterior angles = angle 1 and angle 7</h3>

Similar to alternate interior angles, but now we're outside the black lines. The other pair of alternate exterior angles is angle 2 and angle 8

=======================================================

<h3>Same-side interior angles = angle 3 and angle 6</h3>

The other pair of same-side interior angles is angle 4 and angle 5. They are interior angles, and they are on the same side of the transversal.

6 0
3 years ago
In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th
olya-2409 [2.1K]

Answer:

\frac{BE}{EC} =\frac{1}{3}

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

\frac{BK}{CK} =\frac{1}{4}

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE                ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE     ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK  and Δ EBK are similar

so we have

\frac{AD}{BE} =\frac{DK}{BK}

\frac{AD}{BE} =\frac{4}{1}

\frac{BC}{BE}=\frac{4}{1}     ( ABCD is parallelogram so AD=BC)

\frac{BE+EC}{BE}=\frac{4}{1}         ( BC= BE+EC)

\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}

1+\frac{EC}{BE}=4

\frac{EC}{BE}=3  ( subtracting 1 from both side )

\frac{EC}{BE}=\frac{3}{1}

taking reciprocal both side

\frac{BE}{EC} =\frac{1}{3}


8 0
3 years ago
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