Answer:
To maximize profits, the farmer should plant 120 acres of wheat, and no acre of corn.
Step-by-step explanation:
Given that a farmer plans to grow wheat and corn, and each acre of wheat requires 4 hours of labor and $ 20 of capital, and each acre of corn requires 16 hours of labor and $ 40 of capital, and the farmer has at most 800 hours of labor and $ 2400 of capital available, if the profit from an acre of wheat is $ 80 and from an acre of corn is $ 100, to determine how many acres of each crop should she plant to maximize her profit the following calculation must be performed:
Knowing that each acre of wheat has a 50% lower capital cost, 75% lower hours and a 20% lower profit, in principle this would be the crop to be planted to obtain better yields.
2400/20 = 120
120 x 4 = 480
120 x 80 = 9,600
Thus, to maximize profits, the farmer should plant 120 acres of wheat, and no acre of corn.
Hello!
To the value of b, or the y-intercept, we need to substitute an ordered pair/point into the given equation.
Since we are given two points, we can use those two points to find two different equations.
Remember that ordered pairs are written as (x, y).
A(-2, 4)
y = -3x + b
4 = -3(-2) + b
4 = 6 + b (subtract 6 from both sides)
-2 = b
A) Therefore, the equation of the first ordered pair is y = -3x - 2.
B(5, 2)
2 = -3(5) + b
2 = -15 + b (add 15 to both sides)
17 = b
B) The equation of the second ordered pair is y= -3x + 17.
<u>Final answers</u>:
- A) y = -3x - 2
- B) y = -3x + 17
Answer:
28%
Step-by-step explanation:
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