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Cerrena [4.2K]
3 years ago
15

A composition of transformations maps pre-image EFGH to final image E"F"G"H".

Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0

Answer:

a translation down and left :)

Step-by-step explanation:

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Answer:4(3)/(5)

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You are making a lot of cookies and buy 12 bags of chocolate chips, which are $1.89 per bag
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$22.68

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4 years ago
The express the area of the entire rectangle
Sonja [21]

Answer:

area= x^2+8x+7

Step-by-step explanation:

a=l*w

l=x+7

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a= x^2+8x+7

5 0
4 years ago
is x-1 taking away an x or adding an x?? im trying to find the perimeter of area tiles, and the perimeter is x + x + x + (x-1) +
Vanyuwa [196]

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4x + 2

Step-by-step explanation:

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= 4x + 2

3 0
3 years ago
The mean preparation fee H&amp;R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
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