I don't think so.........
Ah is derived from h^2. it's derivative is 2h^2-1, thus the constant a = 2
b is derived from bh. where it's derivative is h^1-1, thus the constant b = 1
Answer:
y = 2(x-3)^2 -12
y = -4/9(x-2)^2 +7 bonus
Step-by-step explanation:
The vertex form of a parabola is
y = a(x-h)^2 + k where (h,k) is the vertex
y = a(x-3)^2 - 12
We have one point given (0,6)
6 = a (0-3) ^2 -12
6 = a (-3)^2 -12
6 = 9a-12
Add 12 to each side
6+12 = 9a
18 = 9a
Divide each side by 9
18/9 = 9a/9
a=2
y = 2(x-3)^2 -12
We follow the same steps for the bonus
y = a(x-2)^2 +7
Substitute the point into the equation
3 = a (-1-2)^2 +7
3 =a (-3)^2 +7
3 = 9a +7
subtract 7 from each side
3-7 = 9a +7-7
-4 = 9a
Divide by 9
-4/9 =a
y = -4/9(x-2)^2 +7
The first part is 1325
10 x 35=350
15 x 65=975
The you add them which equals 1325
It would be C because a coefficient is always with a variable and 6 is with a variable which makes it a coefficient
Hope this helps
Have a great day/night
