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Alexus [3.1K]
3 years ago
8

If f(×)=3×/2+× find the exact value of f(-4)​

Mathematics
1 answer:
Trava [24]3 years ago
8 0
Go to socrertive and I’ll give you the answer
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Use the variable d to represent the unknown quantity. the product of 4 and the depth of the pool
natka813 [3]

This can be represented by the expression 4d.

6 0
2 years ago
Is 10h - 10 equal to10 - 10h
Black_prince [1.1K]

Answer:no

Step-by-step explanation:

it’s equal to -10 + 10h by the commutativity of addition and subtraction

6 0
2 years ago
Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr
Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

A(t) = A(0)e^{-kt}

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, A(10) = 0.7278A(0). We use this to find k.

A(t) = A(0)e^{-kt}

0.7278A(0) = A(0)e^{-10k}

e^{-10k} = 0.7278

\ln{e^{-10k}} = \ln{0.7278}

-10k = \ln{0.7278}

k = -\frac{\ln{0.7278}}{10}

k = 0.03177289938


Then

A(t) = A(0)e^{-0.03177289938t}

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

A(5) = A(0)e^{-0.03177289938*5}

A(5) = 0.8531

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0
3 years ago
What time is it in eastern time in united states only rob0604 can answer it
wlad13 [49]

Answer:

11:05

Step-by-step explanation:

3 0
3 years ago
My brother is currently three times as old as me, but in five years, my brother
wolverine [178]

Answer: Your brother is 15 years old right now.

Step-by-step explanation:

Let be "m" your currently age and "b" your brother's currently age.

Knowing that right now he is three times (this indicates multiplication) as old as you, you can write the following equation:

b=3m

In five years your age will be:

 m+5

And your brother's age will be:

b+5

Then, if in five years, your  brother will be twice as old as you, you can set up the second equation:

b+5=2(m+5)

Then, the System of equations is:

\left \{ {{b=3m} \atop {b+5=2(m+5)}} \right.

 Apply the Substitution method and substitute the first equation into the second one and solve for "m":

3m+5=2(m+5)\\\\3m+5=2m+10\\\\m=10-5\\\\m=5

Substitute the value of "m" into the first equation and evaluate in order to find "b":

b=3(5)\\\\b=15

4 0
3 years ago
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