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serg [7]
3 years ago
10

What is the Y intercept of the line graphed on the grid

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0

Answer:

5.5

Step-by-step explanation:

The y-intercept of the line graph shown above is the value of the point where the line cuts the y-axis. The y-intercept of this graph is between 5 and 6. However, we can get an accurate value by calculation. This can be done by generating an equation of the line.

Recall the slope-intercept equation, y = mx + b, where m = slope of the line, b = y-intercept.

To generate the equation of the line, first find slope using the points (-2, 7) and (6, 1):

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 7}{6 -(-2)} = \frac{-6}{8} = -\frac{3}{4}.

Substitute m = ¾ and the coordinates (6, 1) into the slope-intercept equation to find the y-intercept (b):

y = mx + b

1 = -\frac{3}{4}(6) + b

1 = -\frac{18}{4} + b

1 = -4.5 + b + 4.5

1 + 4.5 = -4.5 + b + 4.5

5.5 = b

Therefore, b = y-intercept = 5.5.

To generate the equation of the line, plug in the values of m and b, we would have:

y = ¾x + 5.5

The y-intercept of the line of the graph is 5.5.

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3 years ago
A car approaches a stop sign going 10 m/s before coming to a stop. If it takes 5 seconds to
Levart [38]

Answer:

The acceleration is: a = -2 m/s²

The negative sign indicates that velocity is decreasing with time.

Step-by-step explanation:

Given

  • Initial velocity u = 10 m/s
  • Final velocity v = 0
  • Time taken t = 5 seconds

To determine

Acceleration a = ?

Using the formula to determine the acceleration

a = (v - u) / t

substituting u = 10 m/s, v = 0 and t = 5

a = (0 - 10) / 5

a = -10 / 5

a = -2 m/s²

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The acceleration is: a = -2 m/s²

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9.4 the tangent ratio<br> please help on #27 and 28
Ilya [14]

Answer/Step-by-step explanation:

27.

✔️Sin 23 = opp/hyp

Sin 23 = t/34

34*sin 23 = t

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✔️Cos 23 = adj/hyp

Cos 23 = s/34

s = 34*cos 23

s = 31.3

28.

✔️Sin 36 = opp/hyp

Sin 36 = s/5

s = 5*sin 36

s = 2.9

✔️Cos 36 = adj/hyp

Cos 36 = r/5

r = 5*cos 36

r = 4.0

29.

✔️Sin 70 = opp/hyp

Sin 70 = w/10

w = 10*sin 70

w = 9.4

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Cos 70 = v/10

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6 0
3 years ago
In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,
aivan3 [116]

Answer:

Case 1:

AB = 30

BC = 50

Case 2:

AB = 15.9

BC = 36.7

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

AB^2 = AN^2 + BN^2

This gives:

AB^2 = 24^2 + 18^2

AB^2 = 576 + 324

AB^2 = 900

Take square roots of both sides

AB = \sqrt{900

AB = 30

To calculate BC, we consider ANC, where:

AC^2 = AN^2 + NC^2

40^2 = 24^2 + NC^2

1600 = 576 + NC^2

Collect like terms

NC^2 = 1600 - 576

NC^2 = 1024

Take square roots

NC = \sqrt{1024

NC = 32

So:

BC = NC + BN

BC = 32 + 18

BC = 50

Case 2:

Using Pythagoras theorem in ANB, we have:

AN^2 = AB^2 + BN^2

This gives:

24^2 = AB^2 + 18^2

576 = AB^2 + 324

Collect like terms

AB^2 = 576 - 324

AB^2 = 252

Take square roots of both sides

AB = \sqrt{252

AB = 15.9

To calculate BC, we consider ABC, where:

AC^2 = AB^2 + BC^2

40^2 = 252 + BC^2

1600 = 252 + BC^2

Collect like terms

BC^2 = 1600 - 252

BC^2 = 1348

Take square roots

BC = \sqrt{1348

BC = 36.7

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0
3 years ago
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