Answer:
The distance between L and the line KH and HF is;
![27](https://tex.z-dn.net/?f=27)
The value of y is;
![y=9](https://tex.z-dn.net/?f=y%3D9)
Explanation:
Given the figure in the attached image;
![\begin{gathered} KL=27 \\ KHL=(6y)^{\circ} \\ FHL=(4y+18)^{\circ} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20KL%3D27%20%5C%5C%20KHL%3D%286y%29%5E%7B%5Ccirc%7D%20%5C%5C%20FHL%3D%284y%2B18%29%5E%7B%5Ccirc%7D%20%5Cend%7Bgathered%7D)
From the image;
![KL=FL=27](https://tex.z-dn.net/?f=KL%3DFL%3D27)
So, the distance between L and the line KH and HF is;
![27](https://tex.z-dn.net/?f=27)
Also, the triangles KHL and FHL are congruent.
So, the angles KHL and FHL are congruent.
![m\measuredangle KHL\cong m\measuredangle FHL](https://tex.z-dn.net/?f=m%5Cmeasuredangle%20KHL%5Ccong%20m%5Cmeasuredangle%20FHL)
Substituting the expressions;
![\begin{gathered} (6y)^{\circ}=(4y+18)^{\circ} \\ 6y=4y+18 \\ 6y-4y=18 \\ 2y=18 \\ y=\frac{18}{2} \\ y=9 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%286y%29%5E%7B%5Ccirc%7D%3D%284y%2B18%29%5E%7B%5Ccirc%7D%20%5C%5C%206y%3D4y%2B18%20%5C%5C%206y-4y%3D18%20%5C%5C%202y%3D18%20%5C%5C%20y%3D%5Cfrac%7B18%7D%7B2%7D%20%5C%5C%20y%3D9%20%5Cend%7Bgathered%7D)
Therefore, the value of y is;
Answer:
98 sq inc
Step-by-step explanation:
Answer:
18
Step-by-step explanation:
125 = 7x - 1 ...... because if the two lines are parallel alternate interior angles are congruent
125 + 1 = 7x
126 = 7x
![\frac{126}{7} = \frac{7x}{7}](https://tex.z-dn.net/?f=%20%5Cfrac%7B126%7D%7B7%7D%20%20%3D%20%20%5Cfrac%7B7x%7D%7B7%7D%20)
x = 18
hope it helps
for any question comment me ❤❤
Answer: ![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
Step-by-step explanation:
total sides = 6
p (rolling a 1) = ![\frac{1}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D)
p (rolling a 2) = ![\frac{1}{6\\}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%5C%5C%7D)
Note:
or - add
and - multiply
∴ ![\frac{1}{6} +\frac{1}{6} = \frac{2}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%20%2B%5Cfrac%7B1%7D%7B6%7D%20%3D%20%5Cfrac%7B2%7D%7B6%7D)
∴ ![\frac{2}{6} = \frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B6%7D%20%3D%20%5Cfrac%7B1%7D%7B3%7D)
hence, p (rolling a 1 or 2) = ![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)