Answer:
The value of u are,
0.93, -12.93
Step-by-step explanation:
It is given an expression in variable u
(u + 6² + 4 = 52
<u>To find the solution of given expression</u>
(u + 6)·² + 4 = 52
(u + 6)² = 52 - 4
(u + 6)² = 48
u + 6 = √48
u + 6 = ±6.93
u = ±6.93 - 6
u = 6.93 - 6 or u = -6.93 - 6
u = 0.93 or u = -12.93
the large bag is 5/6 lb, the smaller bags will be 1/3 lb, so it should be 5/6 ÷ 1/3
![\bf \cfrac{5}{6}\div \cfrac{1}{3}\implies \cfrac{5}{\underset{2}{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{1}\implies \cfrac{5}{2}\implies 2\frac{1}{2}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B5%7D%7B6%7D%5Cdiv%20%5Ccfrac%7B1%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B%5Cunderset%7B2%7D%7B~~%5Cbegin%7Bmatrix%7D%206%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%5Ccdot%20%5Ccfrac%7B~~%5Cbegin%7Bmatrix%7D%203%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Cimplies%202%5Cfrac%7B1%7D%7B2%7D)
Only 25 and 28 are functions.
A function must have only one y value per x value. For 26, the y value of 0 and multiple others have two different y values. For 27, all x values less than 0 have multiple y values.
Answer:
P____Q____R
PR= PQ+ QR
(14x-13) = (5x-2)+(6x+1)
14x-13= 11x – 1
14x – 11x = 13–1
3x = 12
x= 12/ 3
x= 4
PR= 14x – 13 = 14 (4) – 13 = 18 – 13= 5
If you want (PQ , QR ) this is the solution
PQ =5x-2=5(4)-2=20-2=18
QR =6x+1=6(4)+1=24+1=25
I hope I helped you^_^
Answer:
∫₀² ln(x²) dx
Step-by-step explanation:
An integral is an improper integral if one or both endpoints is infinity, if the function is undefined at one or both endpoints, or if the function is discontinuous between the endpoints.
ln(x²) is undefined at x = 0.
