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Contact [7]
3 years ago
6

PLEASE HELP!!! FOR 60 POINTS!! New York City has two airports (JFK and LGA). If you’re flying with United Airlines (UA) and your

primary concern is to arrive on time, is it better to fly to JFK or to LGA?
Mathematics
2 answers:
scoray [572]3 years ago
6 0

Answer:

JFK

Step-by-step explanation:

The ratings are better, and more people will arrive on time,

worty [1.4K]3 years ago
5 0

Answer:

If you're heading into New York City, LaGuardia is the closest. It's just 8.6 miles from LaGuardia to Midtown Manhattan, compared to 14.7 miles from JFK and 16.6 miles from Newark.

Step-by-step explanation:

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A group of friends has gotten very competitive with their board game nights. They have found that overall, they each have won an
Sati [7]

The standard deviation is  4 games

A standard deviation (or σ) is a measure of how dispersed the facts are in relation to the mean. Low general deviation method statistics are clustered around the imply, and excessive trendy deviation indicates facts are more unfold.

Don't forget the statistics set: 2, 1, 3, 2, four. The mean and the sum of squares of deviations of the observations from the mean will be 2. 4 and 5.2, respectively. as a consequence, the same standard deviation could be √(5.2/5) = 1.01.

In data, the same old deviation is a degree of the quantity of variant or dispersion of a set of values. A low preferred deviation indicates that the values tend to be close to the mean of the set, while a high general deviation shows that the values unfold out over a much broader variety.

Given that,

mean = μ = 18

standard deviation = Σ =  6

n = 2

μ  x =  μ = 18 games

√  x = Σ / √ = 6  

√2 = 4 games

Learn  more about standard deviation here brainly.com/question/12402189

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6 0
2 years ago
For q(x) = x, find x = 1.4
stealth61 [152]

Answer:

1.4

Step-by-step explanation:

q(1.4)=1.4

7 0
3 years ago
Read 2 more answers
What are the domain, range, and asymptote of h(x) = (0.5)x - 9
svetlana [45]

Answer:

The domain of h(x) is {x : x ∈ R}

The range of the function is {y : y > -9}

The horizontal asymptote is at y = -9

Step-by-step explanation:

* Lets read the problem and solve it

- The exponential function is f(x) = a(b)^x, where a and b are constant

  and b is the base , x is the exponent , a is the initial value of f(x)

- The domain of the function is all the values of x which make the

  function defined

- The range of the function is the set of values of y that corresponding

  with the domain x

- Asymptote on the graph a line which is approached by a curve but

 never reached

- A function of the form f(x) = a(b^x) + c always has a horizontal

 asymptote at y = c

* Lets solve the problem

∵ h(x) = (0.5)^x - 9

∵ All the values of x make h(x) defined

∵ The domain of the function is the values of x

∴ The domain of h(x) is {x : x ∈ R} ⇒ R is the set of real number

∵ The range of the function is the set of values of y which

   corresponding to x

∵ (0.5)^x must be positive because there is no values of x make it

  negative value

∴ y must be greater than -9

∴ The range of the function is {y : y > -9}

∵ A function of the form f(x) = a (bx) + c always has a horizontal

   asymptote at y = c

∵ h(x) = (0.5)^x - 9

∴ c = -9

∴ The horizontal asymptote is at y = -9

* Look to the attached file for more understanding

3 0
4 years ago
Read 2 more answers
there are 25 kids who are playing with a parachute, but 45 kids in total can play with the parachute, how many more kids can joi
Fynjy0 [20]
20. 25 + 20 = 45. hope this helps :)
3 0
3 years ago
Read 2 more answers
A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a
Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y  grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)  [as x+y=14]

\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\

\Rightarrow x =(25 \times 14)/32=10.9375 grams

and y = 14-x= 14-10.9375=3.0625 grams.

Hence, 10.9375 grams of 82% gold and 3.0625  grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y  grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\

\Rightarrow x =(50 \times 14)/57=12.28 grams

and y = 14-x= 14-12.28=1.72 grams.

Hence, 12.28 grams of 82% gold and 1.72  grams of 50% gold added to make 14 grams of 75% gold.

3 0
3 years ago
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