Join the centre O to the chord (let it be MN) & let OH be the perpendicular to the chord
OH bisects MN into 2 equal parts (each one is x/2)
OMH is a right triangle with one side =8, the second leg =x/2 & the hypotenuse = 12 (Radius)
Apply Pythagoras:
12² = 8² +(x/2)² ==>144=64 + x²/4 ==> x²=4(144-64) =320
x²=320==> x=√320 =17.88 ≈17.9
Hexagon = 6 sides = 6 x 4 = 24
Octagon = 8 sides = 8
Dodecagons = 12 x 5 = 60
24 + 8 + 60 = 92 IN TOTAL
Answer:
27in
Step-by-step explanation:
So, perimeter means we add all the sides together, as opposed to area, where we multiply them together.
9 - 5 = 4.
So the perimeter of the triangle would be:
3+4+
=12
5 + 5 + 4 +1 (the 1 is from 4 -3) = 15
15 + 12 = 27
Answer:
Ratio 1 = a(240
=b)120
=c)360
Ratio 2=a)400
=b)320
Step-by-step explanation:
On both of the ratios you first add them then divide one by one like this for example 2+1+3= 6
then 2/6 ÷720 = 120 ×2 =240 then you do this to the other numbers as well.
Answer:
The answer is 3x.
Step-by-step explanation:
I broke it down on paper.
