Question

1 kilogram (kg) is about 2.2 times as heavy as 1 pound (lb). Suppose the function f determines Marcus's weight (in lbs), f ( t ) , given the number of days t since the beginning of 2017. The function g determines Marcus's weight (in kg), g ( t ) , given the number of days t since the beginning of 2017. Suppose f ( 29 ) = 194 . What is the value of g ( 29 ) ? g ( 29 ) = Write a formula for g using the function f .

Answer 1

Answer:

1. g(29)=88.18

2. $g(t)=\frac{f(t)}{2.2}$

Step-by-step explanation:

It is given that 1 kilogram (kg) is about 2.2 times as heavy as 1 pound (lb).

1 kg = 2.2 lb

Let as consider f determines Marcus's weight (in lbs), f ( t ) , given the number of days t since the beginning of 2017.

The function g determines Marcus's weight (in kg), g ( t ) , given the number of days t since the beginning of 2017.

It is given that f ( 29 ) = 194, it means the 29 Marcus's weight (in lbs) is 194.

Using the above conversion we get

$1\text{ lb }=\frac{1}{2.2}\text{ kg}$

Multiply both sides by 194.

$194\times 1\text{ lb }=194\times \frac{1}{2.2}\text{ kg}$

$194\text{ lb }=88.181818\text{ kg}$

It means the 29 Marcus's weight (in kg) is about 88.18.

$g(29)=88.18$

Since 1 kg = 2.2 lb, it means weight in kg must be multiplied by 2.2 to convert it into lbs.

$g(t)\times 2.2=f(t)$

Divide both sides by 2.2.

$g(t)=\frac{f(t)}{2.2}$

Therefore the formula for g using the function f is $g(t)=\frac{f(t)}{2.2}$.