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kicyunya [14]
3 years ago
10

Please help with question 15!!! Thank you

Mathematics
1 answer:
kondor19780726 [428]3 years ago
3 0
By the looks your anwser is 1/2

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Three phones in a shipment of eighteen are known to be broken. A randomly selected phone is removed from the shipment and tested
statuscvo [17]

Answer:

\frac{14}{17}

Step-by-step explanation:

Number of phones broken = 3

Number of phones not broken = 15

Total number of phone in the shipment = 18

Since a not broken phone has been randomly selected, the number of phones not broken reduces to 14. And the total number of phones would be 17.

Pr(of newly selected phone NOT broken) = \frac{number of not broken phones}{total number of phones}

                                           = \frac{14}{17}

Therefore, the probability of the selected phone not being broken is \frac{14}{17}.

5 0
3 years ago
Find the value of x. Round to the nearest tenth.<br> Answers<br> A-12.5<br> B-10<br> C-13<br> D-9.7!
kvasek [131]

Answer:   A.  12.5

<u>Step-by-step explanation:</u>

cos\ \theta=\dfrac{adjacent}{hypotenuse}\\\\\\cos\ 28^o=\dfrac{11}{x}\\\\\\\rightarrow\ x=\dfrac{11}{cos\ 28^o}\\\\\\\rightarrow\ x=12.46\\\\\\\rightarrow\ \boxed{x=12.5}\qquad rounded\ to\ the\ nearest\ tenth

6 0
3 years ago
Read 2 more answers
A bug is initially at the point (-3, 7). Where is the bug after being displaced by the vector [-7, 8]?
KiRa [710]

helloAnswer:

Step-by-step explanation:

4 0
3 years ago
Solve the equation. 3p – 1 = 5(p – 1) – 2(7 – 2p) 3 -9 -10 0
Sati [7]

Answer:


Step-by-step explanation:

3p – 1 = 5(p – 1) – 2(7 – 2p) 3 -9 -10  First Distribute

3p-1= 5p-5-42+12p-9-10  Simplify all like factors

3p-1=17p-66 Add 66 on both sides

3p+65=17p Subtract 3p from both sides

65=15p Divide both sides by 15

p=4.3

if it is a 100

3p – 1 = 5(p – 1) – 2(7 – 2p) 3 -9 -100  First Distribute

3p-1= 5p-5-42+12p-9-100  Simplify all like factors

3p-1=17p-156 Add 156 on both sides

3p+155=17p Subtract 3p on both sides

155= 15p divide both sides by 15

10.3=p

3 0
4 years ago
One number is 6 less than 3 times another number and their sum is 62.find the numbers
zysi [14]

y = 6 - 3x

x + y = 62

Since we already know the value of y, we can use substitution to find the value of x.

x + 6 - 3x = 62

<em><u>Subtract 6 from both sides.</u></em>

x - 3x = 56

<em><u>Combine like terms.</u></em>

-2x = 56

<em><u>Divide both sides by -2</u></em>

x = -28

Now that we know the value of x, we can solve for the value of y.

x + y = 62

-28 + y = 62

<em><u>Add 28 to both sides</u></em>

y = 90

The value of y is 90, and the value of x is -28 (this is your answer)

To make sure that these values are correct, we can plug them into the original equations.

y = 6 - 3x

x + y = 62

90 = 6 - 3(-28)

90 = 90 √ this is correct

-28 + 90 = 62

62 = 62 √ this is also correct

3 0
4 years ago
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