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Debora [2.8K]
3 years ago
13

How do you solve the linear equation: 3x+2y=11 7x-y=3 By using the elimination method?!

Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0

<span>
3x + 2y = 11</span>

<span />2(7x - y) = 2(3)

14x-2y=6

Adding both equations<span>
3x + 2y = 11</span>

<span>14x-2y=6</span>

<span>17x=17</span>

<span>x=1</span>

<span>substitute x = 1 in any equation</span>

<span>3(1) + 2y = 11</span>

<span>2y = 8</span>

<span>y = 4</span>

<span>Solution: x=1 y=4</span>

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Pavlova-9 [17]
For this one you can use 3/8 + 3/8 since 3+3 is equals to 6 and the 8 stays as it is.
I hope this helps.
YOU'RE WELCOME :D
4 0
4 years ago
Which statement correctly compares the weight of a newborn beluga and newborn muskox
astraxan [27]
A new born beluga weighs 6 times as much as a newborn muskox.

8 0
3 years ago
6x1 + 9 x 1/10 + 8 x 1/100 + 3 x 1/1000=?
Stolb23 [73]

Answer:

6983/1000 OR 6.983

Step-by-step explanation:

6*1=6

9*1/10=9/10

8*1/100=8/100

3*1/1000=3/1000

6+9/10+8/100+3/1000=6983/1000

OR

6.983

6 0
2 years ago
Pls help! 16 points:)
kenny6666 [7]

Answer: 52 degrees

Step-by-step explanation:

most likley like if correct

7 0
3 years ago
Read 2 more answers
What is the solution set of x2 + y2 = 26 and x − y = 6? A. {(5, -1), (-5, 1)} B. {(1, 5), (5, 1)} C. {(-1, 5), (1, -5)} D. {(5,
Rus_ich [418]
He two equations given are
x^2 + y^2 = 26
And
x - y = 6
x = y +6
Putting the value of x from the second equation to the first equation, we get
x^2 + y^2 = 26
(y + 6) ^2 + y^2 = 26
y^2 + 12y + 36 + y^2 = 26
2y^2 + 12y + 36 - 26 = 0
2y^2 + 12y + 10 = 0
y^2 + 6y + 5 = 0
y^2 + y + 5y + 5 = 0
y(y + 1) + 5 ( y + 1) = 0
(y + 1)(y + 5) = 0
Then 
y + 1 = 0
y = -1
so x - y = 6
     x + 1 = 6
x = 5
Or
y + 5 = 0
y = - 5
Again x = 1
So the solutions would be (-1, 5), (1 , -5). The correct option is option "C".

4 0
3 years ago
Read 2 more answers
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